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【PAT Advanced Level 1026 Table Tennis】关于同一秒钟多个桌子空闲，分配多个客人的情况 #172

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Ceceliawai opened this issue Feb 16, 2024 · 0 comments

Ceceliawai commented Feb 16, 2024

比如说输入以下数据

4
8:00:00 4 0
8:01:00 3 0
8:02:00 1 0
8:02:01 1 0
2 1
1

仓库中的代码输出如下：

08:00:00 08:00:00 0
08:01:00 08:01:00 0
08:02:00 08:04:00 2
08:02:01 08:04:01 2
2 2

但在08:04:00时刻两个桌子都已经空闲，所以最后两位客人的servetime应该都是08:04:00。即同一秒钟可能有多个桌子空闲的情况。

所以或许需要把空闲table的下标放到一个vector里面？~~不过测试点倒是都过了~~

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