Control flow analysis does not take effect of closure of inner functions into account

[jpilgrim]

🔎 Search Terms

literal types, arrow function definition, control flow closure

🕗 Version & Regression Information

• This changed between versions ______ and _______
• This changed in commit or PR _______
• This is the behavior in every version I tried, and I reviewed the FAQ for entries about the terms in the title
• I was unable to test this on prior versions because _______

⏯ Playground Link

https://www.typescriptlang.org/play/?ts=5.8.0-dev.20241121#code/GYVwdgxgLglg9mABMAFFAXIgzlATjMAcwEpEBvAKEWsQBsBTKbTAIgEMXEAfRFgI04BeXhwDcVGhAQ5sYemwDWiYSlKCAfOQk0aWZbwHidAX22IYwRGmWDh-FqUo6dWOYtVGapnRat7bdgKOZjq4jCC4SHgg9J7U3jRhUBFIwGy0WLEUxkA

💻 Code

function f(t: string) {
    let s: "a" | "b" = "a";
    const sneak = () => {
        s = "b";
    }
    if (t === "b") {
        sneak();
    }
    if (s === "b") { // <--- here should be no error!
        return true;
    }
    return false;
}

🙁 Actual behavior

In the line marked with a comment, an error is issued:
This comparison appears to be unintentional because the types '"a"' and '"b"' have no overlap.

🙂 Expected behavior

No error should occur here.

Additional information about the issue

In the example, the control flow analysis apparently does not recognise the effect of the inner function definition or its behaviour when computing the actual type of the variable s. This also happens in case of union types, for example. And it also happens for nested function declarations.

[Andarist]

#9998