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BMATIN6.FORT11
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BMATIN6.FORT11
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SUBROUTINE FENTRY(IJJJ1,IJJJ2,IJJJ3)
C BMATIN6 FINAL MODIFIED VERSION OF PULAY'S BMATIN PROGRAM
C***********************************************************************
C NOTICE OF PROGRAM MODIFICATION *
C***********************************************************************
c Moved to PSI distribution disk on 020389 - clj.
C***********************************************************************
C BY: TPH *
C DATE: DECEMBER 12, 1988 *
C REASON: CORRECT PROBLEM IN DISPLACEMENTS FOR TORSIONS. *
C***********************************************************************
C BY: TPH *
C DATE: SEPT 9, 1988 *
C REASON: CHANGE SCALING OF DISPLACEMENT TO HALVE 5 TIMES. DISP=TRUE *
C***********************************************************************
C BY: TPH *
C DATE: JUNE 13,1988 *
C REASON: PUT IN INVERSE BOND LENGTH AS A COORDINATE - INVR *
C***********************************************************************
C BY: TPH *
C DATE: JUNE 3,1988 *
C REASON: CHANGE SO THAT DUMMY ATOMS CAN BE USED FOR LINEAR BEND *
C DISPLACEMENTS. THE PROGRAM ZOOMS THE DUMMY ATOMS TO A *
C DISTANCE OF 1 BILLION SO THAT LIN1 AND LIN2 ARE EQUIVALENT *
C FOR LINEAR MOLECULES. *
C ALSO SCALE DISPLACEMENT ONCE IN GEOMETRY OPTIMIZATIONS *
C***********************************************************************
C BY: TPH *
C DATE: APRIL 25, 1988 *
C REASON: CHANGE SOME OF THE DEFAULTS. NO LONGER HAVE OLDF, OLDH, *
C AND EXFI. THE PROGRAM WILL READ THEM AND NOT CRASH. *
C NOUP AND NOEX MUST BE SPECIFIED TO SUPRESS HESSIAN UPDATE *
C AND READING IN FROM INP2, WHICH ARE NOW DEFAULT. *
C MURT MUST BE USED TO NOT HAVE POWELL OR BFGS UPDATES *
C***********************************************************************
C BY: TPH *
C DATE: APRIL 23, 1988 *
C REASON: CHANGE MACHB TO USE INTERNAL COORDINATES SPECIFICATION *
C THE SAME AS IN INTDER. (BEND,OUT,LIN1,LIN2) *
C***********************************************************************
C BY: TPH *
C DATE: FEBRUARY 26, 1988 *
C REASON: PUT PARTS BRIAN YATES CHANGED IN HIS VERSION, *
C KEEPING JON BAKER'S OPTEFC NEARLY THE SAME AS IN *
C GAUSSIAN82, AND USING AN INTERFACE CALLED EFC. *
C***********************************************************************
C BY: TPH *
C DATE: FEBRUARY 8, 1988 *
C REASON: PUT COMMENTS IN PROGRAM FIFTH, RENUMBER *
C INDICATING WHERE CHANGES IN THE NEAR FUTURE WILL BE MADE *
C***********************************************************************
C BY: TPH *
C DATE: OCTOBER 26, 1987 *
C REASON: PUT IN EIGENVECTOR FOLLOWING ROUTINE OF JON BAKER, *
C POWELL UPDATE OF THE HESSIAN, AND DIIS FOR GEOMETRY OPT. *
C BESSLER PREVIOUSLY PUT IN BFGS AND DAVIDON-FLETCHER-POWELL *
C UPDATES. FILE INP4 HAS INTERNAL FORCES PREVIOUS STEPS. *
C FILE INP3 HAS THE EIGENVECTOR FROM PREVIOUS STEP IN OPTEFC.*
C***********************************************************************
C***********************************************************************
C FUTURE NEEDS FOR BMAT: TAKE CARE OF DISCONTINUITY IN ANGULAR *
C COORDINATES (FOR NOW CHANGING ANGLE DEFINITIONS MAY HELP), *
C FIX GDIIS, PRINT RMS GRADIENT, *
C AUTOMATIC ROTATION SO THAT ONE COORDINATE IS AT ORIGIN *
C OR SYMMETRY PLANE PRESERVED ETC., *
C CALCULATION OF # OF TOTALLY SYMMETRIC MODES FOR WARNINGS *
C STEP LENGTH CONTROL FOR REGULAR BMAT *
C***********************************************************************
IMPLICIT DOUBLE PRECISION (A-H,O-Z)
CHARACTER AI*80,WKEY1*4,WKEY2*4
INTEGER INP,IOUT,INP2,IPUN,IGMUP
COMMON /IOP/ IOP(50)
COMMON /GANZ/ NA,LOPT(26)
PARAMETER(INP=30,IOUT=31,INP2=32,IPUN=33,IGMUP=5)
PARAMETER(WKEY1='BMAT',WKEY2='STOP')
C....................................................................
C THIS IS WRITTEN SO THAT SEVERAL BMAT SECTIONS IN THE BMAT .
C INPUT FILE CAN BE RUN, SHOULD THE NEED ARISE .
C....................................................................
CALL NOUNFL
10 READ (INP,50) AI
IF (AI(1:4).NE.WKEY1) GO TO 40
WRITE(IOUT,60)
WRITE(IOUT,70) AI
DO 20 I=1,50
IOP(I)=0
20 CONTINUE
DO 30 I=1,26
LOPT(I)=0
30 CONTINUE
CALL FIFTH (INP,IOUT,INP2,IPUN,IGMUP)
GO TO 10
40 CONTINUE
50 FORMAT (A80)
60 FORMAT (9(8H********))
70 FORMAT (//,1X,A80)
END
C //////////////////////////////////////////////////////////
SUBROUTINE FIFTH(INP,IOUT,INP2,IPUN,IGMUP)
IMPLICIT REAL*8 (A-H,O-Z)
INTEGER INP,IOUT,INP2,IPUN,IGMUP
INTEGER P,Q,NR
CHARACTER WO*4,WK(26)*4,W1*2
INTEGER INDI(4,50),INDT(4)
LOGICAL WRIT,IFSTRE(50),SFIRST,DISP
REAL*8 NV,N2V,N3V
DIMENSION CCIN(4,50),CIN(4),CCC(75),ETA(4),ENERGY(4)
DIMENSION CI(9),AE(3),DUMX(10),DUMY(10),DUMZ(10)
DIMENSION SYMB(25)
DIMENSION LFLAG(4)
DIMENSION QQQ(69),FII(69)
DIMENSION WW(2)
DIMENSION L(69),M(69), KI(75), IA(25)
DIMENSION IFIX(20),IBOHR(40)
COMMON/MODOUT/VMODE(50)
COMMON /ENER/ TITLE(16)
COMMON /GANZ/ NA,LOPT(26)
COMMON /IO/ IIN,IIOUT,IINP2,IIPUN,IIGMUP
COMMON /IOP/ IOP(50)
COMMON/DISCON/SSS(100),SFIRST
COMMON /BMAT/ BL(1),C(4761),F(75),FI(69),CC(75)
&,XA(25),YA(25),ZA(25)
&,XM(75),XY(75),QQ1(75),QQ(69),B(75,69)
&,NV(75),HE(69,69),HN(69,69)
&,N2V(69),DV(69),N3V(69),GRC(69),GEC(69),A(4761),QD(69,69)
&,FD(69,69)
EQUIVALENCE (B(1,1),WW(1))
PARAMETER(ZERO=0.0D0,HALF=0.5D0,ONE=1.0D0,TWO=2.0D0)
PARAMETER(THREE=3.0D0,FOUR=4.0D0,FIVE=5.0D0,TEN=10.0D0)
PARAMETER(ANG=1.889726664D0,GDYN=8.2388575D0)
PARAMETER(FSUMT=1.0D-7,CRTTOL=1.0D-12,MXITER=40)
PARAMETER(RADC=57.29577951308D0)
DATA (WK(I),I=1,6)/'CARD','FMAT','DISP','OLDF','PUNC','PRIN'/
DATA (WK(I),I=7,12)/'ANGS','FIXC','FINT','FLT1','EXFI','BOHR'/
DATA (WK(I),I=13,18)/'FLT2','GDYN','OLDH','DEGR','DFLP','BFGS'/
DATA (WK(I),I=19,23)/'POWL','EIGF','DIIS','MODE','DUMB'/
DATA (WK(I),I=24,26)/'NOUP','NOEX','MURT'/
DATA XNIST/2HN=/
REWIND INP2
SFIRST=.TRUE.
DISP=.TRUE.
IIN=INP
IIOUT=IOUT
IINP2=INP2
IIPUN=IPUN
IIGMUP=IGMUP
IOP(5)=1
IX=INP
ISCALE=0
NDUM=0
NMAX=25
NCMAX=3*NMAX
NQMAX=NCMAX-6
LFLAG(1)=0
NFIX=0
C
C DIMENSION OF THE B MATRIX MUST CONFORM TO B(NCMAX,NQMAX)
C.................................................................
C READ IN INPUT OPTIONS .
C.................................................................
10 READ(INP,2000) WO,NR
DO 20 I=1,26
IF (WK(I).EQ.WO) GO TO 30
20 CONTINUE
BACKSPACE INP
GO TO 40
30 LOPT(I)=1
IF(I.EQ.1) NA=NR
IF (I.EQ.3) LOPT(3)=NR
IF (I.EQ.3.AND.LOPT(3).EQ.0) LOPT(3)=1
IF(I.EQ.8) THEN
NFIX=NFIX+1
IFIX(NFIX)=NR
END IF
IF(I.EQ.10) THEN
BACKSPACE INP
READ(INP,2020) WO,ETA(1),ETA(2),ETA(3),ETA(4)
WRITE(IOUT,2025) WO,ETA(1),ETA(2),ETA(3),ETA(4)
GO TO 10
END IF
IF(I.EQ.13) THEN
BACKSPACE INP
READ(INP,2030) WO,(ETA(K),ENERGY(K),K=1,3)
WRITE(IOUT,2035) WO,(ETA(K),ENERGY(K),K=1,3)
LOPT(10)=1
GO TO 10
END IF
IF(I.EQ.20) THEN
BACKSPACE INP
READ(INP,2040) WO,IOP(5),IOP(7),IOP(8),IOP(13),IOP(16),
& IOP(17),IOP(19),IOP(33),IOP(34)
WRITE(IOUT,2045) WO,IOP(5),IOP(7),IOP(8),IOP(13),IOP(16),
& IOP(17),IOP(19),IOP(33),IOP(34)
GO TO 10
END IF
IF(I.EQ.22) THEN
BACKSPACE INP
READ(INP,2050) WO,MODE1,MODE2
WRITE(IOUT,2055) WO,MODE1,MODE2
GO TO 10
END IF
IF(I.EQ.23) THEN
BACKSPACE INP
NDUM=NDUM+1
READ(INP,2060) WO,DUMX(NDUM),DUMY(NDUM),DUMZ(NDUM)
WRITE(IOUT,2065) WO,DUMX(NDUM),DUMY(NDUM),DUMZ(NDUM)
GO TO 10
END IF
WRITE(IOUT,2010) WO,NR
GO TO 10
C..................................................................
C CHECK THE NUMBER OF ITERATIONS .
C..................................................................
40 CONTINUE
READ(INP2,2070) NGEO,NUMIT
C..................................................................
C SET THE DEFAULTS HERE .
C..................................................................
IF(LOPT(3).GT.0.OR.LOPT(10).GT.0.OR.LOPT(13).GT.0) DISP=.FALSE.
IF(LOPT(10).GT.0) THEN
LOPT(15)=1
IF(LOPT(24).NE.0) LOPT(15)=0
ELSE
LOPT(4)=1
IF(LOPT(24).NE.0) LOPT(4)=0
ENDIF
IF(LOPT(25).GT.0) THEN
LOPT(11)=0
ELSE
LOPT(11)=1
ENDIF
IF(LOPT(17).EQ.0.AND.LOPT(18).EQ.0.AND.LOPT(19).EQ.0.AND.
& LOPT(26).EQ.0) THEN
IF(IOP(5).EQ.1) LOPT(18)=1
IF(IOP(5).EQ.0) LOPT(19)=1
ENDIF
C WRITE(IOUT,1234) (LOPT(I),I=1,26)
C1234 FORMAT(26I3)
C..................................................................
C TURN OFF HESSIAN UPDATING IN OPTEFC UNLESS BFGS WITH .
C POSITIVE DEFINITENESS IS GUARANTEED. .
C..................................................................
IF(LOPT(18).EQ.1 .AND. IOP(13).EQ.2) THEN
LOPT(24) = 1
ELSE
IOP(13) = -1
ENDIF
IF(LOPT(11).EQ.0.OR.NUMIT.LT.1) GO TO 60
C..................................................................
C CHECK THE NUMBER OF ATOMS IN INP2 IS EQUAL NA (EXFI OPTION) .
C..................................................................
DO 50 I=1,NA
READ(INP2,2080) W1
IF(W1.NE.'N=') THEN
WRITE(IOUT,2090) W1
RETURN
END IF
50 CONTINUE
60 CONTINUE
C..................................................................
C CHECK THAT NA IS NOT LARGER THAN NMAX .
C..................................................................
IF (NA.GT.0.AND.NA.LE.NMAX) GO TO 70
WRITE (IOUT,2100) NA
RETURN
70 CONTINUE
CTPH N=NA
IF (LOPT(1).NE.1) THEN
WRITE(IOUT,2105)
STOP
ENDIF
C..................................................................
C READ GEOMETRY IN FROM BMAT FILE .
C..................................................................
WRITE( IOUT,2110)
DO 90 I=1,NA
I3=3*I
READ(INP,2120) SYMB(I),IA(I),XA(I),YA(I),ZA(I),XM(I3)
C..................................................................
C DEFAULT MASS IS ONE .
C..................................................................
IF (XM(I3).EQ.ZERO) XM(I3)=ONE
IF (LOPT(7).EQ.1) GO TO 80
C..................................................................
C CONVERT BOHR TO ANGSTROMS .
C..................................................................
XA(I)=XA(I)/ANG
YA(I)=YA(I)/ANG
ZA(I)=ZA(I)/ANG
80 CONTINUE
C..................................................................
C CONVERT ANGSTROMS TO BOHR FOR PRINTING .
C..................................................................
XXWA=XA(I)*ANG
YYWA=YA(I)*ANG
ZZWA=ZA(I)*ANG
WRITE(IOUT,2130) I,IA(I),XXWA,YYWA,ZZWA,XM(I3)
C..................................................................
C PUT INVERSE MASS IN XM .
C..................................................................
XM(I3)=ONE/XM(I3)
XM(I3-1)=XM(I3)
XM(I3-2)=XM(I3)
90 CONTINUE
C..................................................................
NEK=3*NA
IF (LOPT(3).GT.0) GO TO 130
IF (LOPT(9).GT.0) GO TO 190
C..................................................................
C READ FORCES IN FROM BMAT FILE .
C..................................................................
READ (INP,2140) (F(I),I=1,NEK)
IF(LOPT(14).EQ.1) GO TO 110
C..................................................................
C CONVERT GRADIENTS IN ATOMIC UNITS TO FORCES IN MDYN .
C..................................................................
DO 100 I=1,NEK
F(I)=-F(I)*GDYN
100 CONTINUE
110 CONTINUE
WRITE(IOUT,2150)
WRITE(IOUT,2160) (F(I),I=1,NEK)
C..................................................................
C CHECK THAT FORCES ADD TO ZERO .
C..................................................................
XFQX=F(1)
DO 120 I=2,NEK
120 XFQX=XFQX+F(I)
IF(DABS(XFQX).GT.FSUMT) WRITE (IOUT,2170) XFQX
IF(LOPT(3).LE.0) GO TO 190
C..................................................................
C READ IN DISPLACEMENTS .
C..................................................................
130 CONTINUE
NDI=LOPT(3)
DO 140 I=1,NDI
140 READ (INP,2180) (INDI(J,I),CCIN(J,I),J=1,4)
IF(LOPT(12).NE.1) GO TO 190
C..................................................................
C CHANGE DISPLACEMENTS TO BOHR INSTEAD OF ANGSTROMS .
C..................................................................
NBOHR=0
IQ=0
KB=0
150 KB=KB+1
READ(INP,2190) WO,W1
IF(WO(1:1).NE.'K'.AND.WO.NE.' ') GO TO 160
IF(WO(1:1).EQ.'K')THEN
IQ=IQ+1
IF(W1.EQ.'ST')THEN
NBOHR=NBOHR+1
IBOHR(NBOHR)=IQ
END IF
END IF
GO TO 150
160 DO 170 I=1,KB
170 BACKSPACE INP
DO 180 K=1,NBOHR
DO 180 I=1,NDI
DO 180 J=1,4
IF(INDI(J,I).EQ.IBOHR(K))THEN
CCIN(J,I)=CCIN(J,I)/ANG
ELSE IF (LOPT(16).EQ.1) THEN
CCIN(J,I)=CCIN(J,I)/RADC
END IF
180 CONTINUE
C....................................................................
C PUT DUMMY ATOM COORDINATES IN XA,YA,ZA (NOT COMPLETELY TESTED).
C....................................................................
190 CONTINUE
NADT=NA
IF (LOPT(3) .NE. 0) THEN
NADT=NADT+NDUM
BILION = 1000000000.0D0
IF(NADT.GT.NMAX) STOP 'NA+NDUM GREATER THAN NMAX'
DO 200 I=1,NDUM
DUNORM = DSQRT(DUMX(I)**2 + DUMY(I)**2 + DUMZ(I)**2)
XA(NA+I)=DUMX(I)*BILION/DUNORM
YA(NA+I)=DUMY(I)*BILION/DUNORM
ZA(NA+I)=DUMZ(I)*BILION/DUNORM
NEK = NEK+3
200 CONTINUE
ENDIF
WRIT=.FALSE.
IF (LOPT(6).EQ.1) WRIT=.TRUE.
C....................................................................
C CHECK THE TYPE OF INTERNAL COORDINATE FOR OPTEFC CONVERSION .
C OF ANGSTROMS TO BOHRS .
C....................................................................
IQ=0
KB=0
205 KB=KB+1
READ(INP,2190) WO,W1
IF(WO(1:1).NE.'K' .AND. WO.NE.' ') GO TO 206
IF(WO(1:1).EQ.'K') THEN
IQ=IQ+1
IFSTRE(IQ) = W1.EQ.'ST'
ENDIF
GO TO 205
206 CONTINUE
DO 207 I=1,KB
BACKSPACE INP
207 CONTINUE
C....................................................................
C MAKE B MATRIX .
C....................................................................
CALL MACHB (NEK,B,NCMAX,NQMAX,XA,YA,ZA,QQ,NADT,IX,IOUT,NQ,WRIT,
1.FALSE.,NCARD)
IF(LOPT(5).EQ.0) GO TO 220
C....................................................................
C PUNCH B MATRIX .
C....................................................................
WRITE(IPUN,2200)
WRITE (IPUN,2210)
DO 210 I=1,NQ
WRITE (IPUN,2220) I
WRITE (IPUN,2230) (B(J,I),J=1,NEK)
210 CONTINUE
220 CONTINUE
C....................................................................
C INVERT B*M*B+ (SEE PULAY'S ARTICLE IN VOL 4, P 166) .
C....................................................................
I1=0
DO 240 I=1,NQ
DO 240 J=1,NQ
I1=I1+1
S=ZERO
DO 230 K=1,NEK
230 S=S+B(K,I)*B(K,J)*XM(K)
240 C(I1)=S
TOL=1.0D-8
CALL OSINV1 (C,NQ,D,TOL,L,M)
C....................................................................
WRITE (IOUT,2240) D
IF (LOPT(3).GT.0) GO TO 1150
C....................................................................
C FORM B*M*F .
C....................................................................
WRITE( IOUT,2250)
DO 260 I=1,NQ
T=ZERO
DO 250 J=1,NEK
250 T=T+B(J,I)*F(J)*XM(J)
260 CC(I)=T
C....................................................................
C FORM (B*M*B+)-1 * B*M*F = INTERNAL FORCES .
C....................................................................
IJ=0
DO 300 I=1,NQ
T=ZERO
IF(LOPT(9).GT.0) GO TO 280
DO 270 J=1,NQ
IJ=IJ+1
270 T=T+C(IJ)*CC(J)
FI(I)=T
280 IF(LOPT(9).LE.0) GO TO 290
C....................................................................
C READ IN INTERNAL FORCES INSTEAD .
C....................................................................
READ(INP,2140) FI(I)
NCARD=NCARD+1
290 CONTINUE
C....................................................................
C WRITE OUT COORDINATE NUMBER, INTERNAL COORDINATE AND FORCE .
C....................................................................
WRITE (IOUT,2260) I,QQ(I),FI(I)
QQQ(I)=QQ(I)
FII(I)=FI(I)
300 CONTINUE
C....................................................................
C PUNCH INTERNAL FORCES .
C....................................................................
WRITE(IPUN,2270) (FI(I),I=1,NQ)
IF(LOPT(10).GE.1.AND.LOPT(13).LT.1) WRITE(IOUT,2280)
IF(LOPT(13).GE.1) WRITE(IOUT,2290)
IF (LOPT(2).LT.1) GO TO 1530
C....................................................................
C READ INTERNAL FORCE CONSTANT MATRIX FROM BMAT FILE OR INP2 .
C....................................................................
IF(LOPT(10).GE.1) THEN
WRITE(IOUT,2300)
ELSE
WRITE(IOUT,2310)
END IF
IF(LOPT(11).GT.0.AND.NUMIT.GT.0) IX=INP2
DO 320 I=1,NQ
READ(IX,2270)(F(J),J=1,I)
WRITE (IOUT,2320) (F(J),J=1,I)
IF (LOPT(11).GT.0.AND.NUMIT.GT.0) GO TO 310
C....................................................................
C NCARD KEEPS TRACK OF HOW MANY CARDS IT TAKES IN BMAT FILE .
C TO READ IN THE FORCE CONSTANT MATRIX, FOR LATER USE .
C....................................................................
NCARD=NCARD+1+(I-1)/8
310 CONTINUE
C....................................................................
C PUT FORCE CONSTANT IN SQUARE MATRIX C, TAKE THE INVERSE .
C....................................................................
DO 320 J=1,I
IJ=(I-1)*NQ+J
JI=(J-1)*NQ+I
C(JI)=F(J)
C(IJ)=C(JI)
320 CONTINUE
IX=INP
CALL OSINV1 (C,NQ,D,1.0D-8,L,M)
IF(NUMIT.LT.1) GO TO 870
C....................................................................
C READ IN OLD INTERNAL COORDINATES, FORCES, AND DISPLACEMENTS .
C FROM INP2 OR INP .
CTPH INP2 SHOULD HAVE THIS WHETHER EXFI IS USED OR NOT .
C....................................................................
IF(LOPT(11).GT.0) IX=INP2
DO 340 I=1,NQ
READ(IX,2340) CC(I),F(I),GEC(I)
IF(LOPT(11).GT.0.AND.NUMIT.GT.0) GO TO 330
NCARD=NCARD+1
330 CONTINUE
340 CONTINUE
MODE= 0
IF(NUMIT.GT.0.AND.LOPT(11).GT.0) READ(INP2,2620) MODE
IX=INP
IF (LOPT(4).LT.1.AND.LOPT(15).LT.1) GO TO 870
C....................................................................
C UPDATE THE HESSIAN UNLESS IT IS THE FIRST OPTIMIZATION CYCLE .
C ALL UPDATES ARE THE POWELL UPDATE THE INVERSE HESSIAN .
C....................................................................
WRITE(IOUT,2330)
CTPH IF(LOPT(11).GT.0) IX=INP2
DO 345 I=1,NQ
WRITE (IOUT,2260) I,CC(I),F(I)
345 CONTINUE
CTPH IX=INP
C..................................................................
IF(LOPT(15).GE.1) GO TO 820
IF(LOPT(17) .EQ. 1) GOTO 420
IF(LOPT(18) .EQ. 1) GOTO 520
IF(LOPT(19) .EQ. 1) GOTO 620
C....................................................................
C MURTAGH-SARGENT UPDATE .
C....................................................................
WRITE(IOUT,2350)
DO 350 I=1,NQ
GRC(I)=-FI(I)+F(I)
350 CONTINUE
C 350 GEC(I)=QQ(I)-CC(I)
IJ=0
DO 360 I=1,NQ
DO 360 J=1,NQ
IJ=IJ+1
360 HE(I,J)=C(IJ)
DO 370 I=1,NQ
NV(I)=0.D0
DO 370 J=1,NQ
370 NV(I)=NV(I)+HE(I,J)*GRC(J)
DO 380 I=1,NQ
380 NV(I)=GEC(I)-NV(I)
DN=0.D0
DO 390 I=1,NQ
390 DN=DN+NV(I)*GRC(I)
DO 400 I=1,NQ
DO 400 J=1,NQ
400 HE(I,J)=HE(I,J)+NV(I)*NV(J)/DN
IJ=0
DO 410 I=1,NQ
DO 410 J=1,NQ
IJ=IJ+1
410 C(IJ)=HE(J,I)
GOTO 820
420 CONTINUE
C....................................................................
C DAVIDON-FLETCHER-POWELL (DFP) UPDATE .
C....................................................................
WRITE(IOUT,2360)
DO 430 I=1,NQ
GRC(I)=-FI(I)+F(I)
430 CONTINUE
C 430 GEC(I)=QQ(I)-CC(I)
IJ=0
DO 440 I=1,NQ
DO 440 J=1,NQ
IJ=IJ+1
440 HE(I,J)=C(IJ)
DN=0.D0
DO 450 I=1,NQ
450 DN=DN+GEC(I)*GRC(I)
DO 460 I=1,NQ
DO 460 J=1,NQ
460 HN(I,J)=GEC(I)*GEC(J)/DN
DO 470 I=1,NQ
DV(I)=0.D0
DO 470 J=1,NQ
470 DV(I)=DV(I)+HE(I,J)*GRC(J)
DN=0.D0
DO 480 I=1,NQ
480 DN=DN+GRC(I)*DV(I)
DO 490 I=1,NQ
N2V(I)=0.D0
DO 490 J=1,NQ
490 N2V(I)=N2V(I)+GRC(I)*HE(I,J)
DO 500 I=1,NQ
DO 500 J=1,NQ
500 HE(I,J)=HE(I,J)+HN(I,J)-DV(I)*N2V(J)/DN
IJ=0
DO 510 I=1,NQ
DO 510 J=1,NQ
IJ=IJ+1
510 C(IJ)=HE(I,J)
GOTO 820
520 CONTINUE
C....................................................................
C BFGS UPDATE .
C....................................................................
WRITE(IOUT,2370)
DO 530 I=1,NQ
GRC(I)=-FI(I)+F(I)
530 CONTINUE
C 530 GEC(I)=QQ(I)-CC(I)
IJ=0
DO 540 I=1,NQ
DO 540 J=1,NQ
IJ=IJ+1
540 HE(I,J)=C(IJ)
DN=0.D0
DO 550 I=1,NQ
550 DN=DN+GEC(I)*GRC(I)
DO 560 I=1,NQ
NV(I)=0.D0
DO 560 J=1,NQ
560 NV(I)=NV(I)+GRC(J)*HE(I,J)
SU=0.D0
DO 570 I=1,NQ
570 SU=SU+NV(I)*GRC(I)
SU=1.D0+SU/DN
DO 580 I=1,NQ
DO 580 J=1,NQ
580 HN(I,J)=HN(I,J)+SU/DN*GEC(I)*GEC(J)
DO 590 I=1,NQ
N2V(I)=0.D0
DO 590 J=1,NQ
590 N2V(I)=N2V(I)+GRC(J)*HE(I,J)
DO 600 I=1,NQ
DO 600 J=1,NQ
600 HE(I,J)=HE(I,J)+HN(I,J)-GEC(I)*N2V(J)/DN-NV(I)*GEC(J)/DN
IJ=0
DO 610 I=1,NQ
DO 610 J=1,NQ
IJ=IJ+1
610 C(IJ)=HE(I,J)
GO TO 820
620 CONTINUE
C......................................................................
C POWELL UPDATE (SYMMETRIC BROYDEN) .
C INVERT C TO REGAIN THE HESSIAN, UPDATE, THEN RESTORE THE INVERSE.
C......................................................................
CALL OSINV1 (C,NQ,D,1.0D-8,L,M)
WRITE(IOUT,2380)
IJ=0
DO 630 I=1,NQ
DO 630 J=1,NQ
IJ=IJ+1
630 HE(I,J)=C(IJ)
CTPH DO 640 I=1,NQ
CTPH GEC(I)=QQ(I)-CC(I)
C 640 CONTINUE
DO 660 I=1,NQ
N2V(I)=0.0D0
DO 650 J=1,NQ
N2V(I)=N2V(I)+HE(I,J)*GEC(J)
650 CONTINUE
GRC(I)=-FI(I)+F(I)-N2V(I)
660 CONTINUE
DN=0.D0
DO 670 I=1,NQ
670 DN=DN+GEC(I)*GEC(I)
SU=0.D0
DO 680 I=1,NQ
680 SU=SU+GEC(I)*GRC(I)
SU=SU/DN
DABSSU=DABS(SU)
C....................................................................
C YOU MAY NOT WANT TO DO THE UPDATE IF THE DISPLACEMENT IS SMALL.
C....................................................................
CTPH IF(DN.LT.0.000001D0) GO TO 700
DO 690 I=1,NQ
DO 690 J=1,I
TEMP=GEC(I)*GRC(J)+GEC(J)*GRC(I)-GEC(I)*SU*GEC(J)
HE(I,J)=HE(I,J)+TEMP/DN
HE(J,I)=HE(I,J)
690 CONTINUE
700 CONTINUE
IJ=0
DO 710 I=1,NQ
DO 710 J=1,NQ
IJ=IJ+1
710 C(IJ)=HE(I,J)
CALL OSINV1 (C,NQ,D,1.0E-8,L,M)
C....................................................................
C THE OPTIMALLY CONDITIONED UPDATE SHOULD GO HERE .
C....................................................................
820 IF(LOPT(4).GE.1) GO TO 870
C....................................................................
C UPDATE THE FLETCHER POWELL FORCE CONSTANTS .
C....................................................................
IJ=0
DO 840 I=1,NQ
S=ZERO
DO 830 J=1,NQ
IJ=IJ+1
830 S=S-C(IJ)*F(J)
840 CCC(I)=S
S=ZERO
S1=ZERO
DO 850 I=1,NQ
S=S-CC(I)*F(I)
850 S1=S1+CCC(I)*F(I)
IJ=0
DO 860 I=1,NQ
DO 860 J=1,NQ
IJ=IJ+1
860 C(IJ)=C(IJ)+CC(I)*CC(J)/S+CCC(I)*CCC(J)/S1
870 CONTINUE
C....................................................................
C CALCULATE THE NEW COORDINATES IN ONE OF THREE WAYS: .
C (A) EIGENVECTOR FOLLOWING (B) DIIS (C) NEWTON-RAPHSON .
C....................................................................
IF(LOPT(20).GE.1) THEN
C....................................................................
C (A) EIGENVECTOR FOLLOWING, EFC IS AN INTERFACE BETWEEN .
C BMATIN6 AND OPTEFC WRITTEN BY BRIAN YATES .
C THE HESSIAN IS NEEDED INSTEAD OF ITS INVERSE .
C....................................................................
CTPH MODE = 0
IF(LOPT(22).EQ.1 .AND. NUMIT.LT.1) THEN
IF(MODE1.EQ.1) MODE = MODE2
IF(MODE1.EQ.0) MODE = MODE2 + NQ
ENDIF
CALL OSINV1 (C,NQ,D,1.0D-8,L,M)
CALL EFC(NUMIT,NQ,F,QQ,FI,C,MODE,QQ1,IFSTRE,GEC)
CALL OSINV1 (C,NQ,D,1.0D-8,L,M)
ELSE
IF(LOPT(21).GT.0) NGEO=NGEO+1
IF(NGEO.GT.1.AND.LOPT(21).GT.0) THEN
C....................................................................
C (B) DIIS WITH THE POSSIBILITY OF UPDATING THE HESSIAN; THEREFORE .
C THE ERROR VECTORS MUST BE RECALCULATED FROM THE PREVIOUS AND .
C PRESENT GRADIENTS, USING THE NEW HESSIAN E = (H)-1*G .
C....................................................................
C....................................................................
C READ IN PAST COORDINATES AND GRADIENTS INTO QD AND FD .
C....................................................................
IF(NGEO.GE.NQ) NGEO = NQ-1
DO 880 J=1,NGEO-1
DO 880 I=1,NQ
READ(INP2,2390) QD(I,J),FD(I,J)
880 CONTINUE
M1=NGEO+1
MM1=NQ
MNQ=NMAX
DO 890 I=1,NQ
FD(I,NGEO)=FI(I)
QD(I,NGEO)=QQ(I)
890 CONTINUE
CALL GDIIS(MM1,NQMAX,M1,NQ,QD,FD,C,A,NV,N2V,QQ,FI,DV,XLAM,IER)
CTPH.................................................................
C EXTRAPOLATED COORDINATES AND FORCES IN QQ AND FI, THEN RELAX .
C PRINTING OF DIIS MATRIX FOR DEBUGGING, TO BE CHANGED LATER .
CTPH.................................................................
WRITE(IOUT,2401)
2401 FORMAT('INVERSE HESSIAN')
DO 901 I=1,NQ
J1=(I-1)*NQ+1
JN=(I-1)*NQ+I
WRITE(IOUT,2270) (C(J), J=J1,JN)
901 CONTINUE
WRITE(IOUT,2400)
DO 900 I=1,M1
J1=(I-1)*M1+1
JN=(I-1)*M1+I
WRITE(IOUT,2270) (A(J), J=J1,JN)
900 CONTINUE
IF (IER.EQ.0) GO TO 910
CTPH.................................................................
C ERROR SECTION, TO BE CHANGED LATER TO STOP PROGRAM .
CTPH.................................................................
WRITE(IOUT,2405)
RETURN
910 CONTINUE
C....................................................................
C PUT INTERNAL DISPLACEMENTS AND OLD INT. COORDINATES IN QQ1, QQ.
C....................................................................
CC DO 930 I=1,NQ
CC QQ1(I)=QQ(I)-QD(I,NGEO)
CC QQ(I)=QD(I,NGEO)
CC930 CONTINUE
WRITE(IOUT,2320) (QQ(I),I=1,NQ)
WRITE(IOUT,2320) (FI(I),I=1,NQ)
WRITE(IOUT,2410) (DV(I),I=1,NGEO)
WRITE(IOUT,2420) XLAM
ENDIF
C....................................................................
C (C) NEWTON RAPHSON STEP WHICH IS THE DEFAULT .
C....................................................................
IJ=0
DO 950 I=1,NQ
S=ZERO
DO 940 J=1,NQ
IJ=IJ+1
S=S+C(IJ)*FI(J)
940 CONTINUE
QQ1(I)=S
950 CONTINUE
ENDIF
C....................................................................
C CALCULATE FLAMBDA FOR FLETCHER PROCEDURE, PRINT NEW INTERNAL .
C COORDINATES AND DISPLACEMENTS, PUT DISPLACEMENTS IN GEC FOR .
C WRITING TO RESUL2 LATER .
C....................................................................
IF(LOPT(10).GE.1) THEN
WRITE(IOUT,2430)
ELSE
WRITE(IOUT,2440)
END IF
FLAMDA=0.0D0
DO 960 I=1,NQ
FLAMDA=FLAMDA+QQ1(I)*FII(I)
IF(NGEO.GT.1.AND.LOPT(21).GT.0) QQ1(I)=QQ(I)+QQ1(I)-QD(I,NGEO)
GEC(I)=QQ1(I)
CC(I)=GEC(I)
960 CONTINUE
C....................................................................
C SET CERTAIN DISPLACEMENTS TO ZERO (FIXC OPTION) .
C....................................................................
IF(NFIX.GT.0) THEN
DO 970 I=1,NFIX
CC(IFIX(I))=ZERO
QQ1(IFIX(I))=ZERO
GEC(IFIX(I))=ZERO
970 CONTINUE
ENDIF
DO 975 I=1,NQ
WRITE (IOUT,2260) I,QQ1(I),QQ(I)+QQ1(I)
975 CONTINUE
C....................................................................
C REGAIN THE HESSIAN FROM THE INVERSE .
C....................................................................
980 CALL OSINV1 (C,NQ,D,1.0E-8,L,M)
IF(LOPT(4).GT.0.OR.LOPT(15).GT.0) GO TO 1010
C....................................................................
C CHECK THE FORCE CONSTANTS TO SEE WHICH FORMAT TO USE, PRINT .
C IN FILE INP2 .
C....................................................................
REWIND INP2
JTRI=NQ*(NQ+1)/2
IBIG=0
DO 990 J=1,JTRI
IF(C(J).LE.-10.0D0.OR.C(J).GE.100.0D0) IBIG=1
990 CONTINUE
IJ=1
DO 1000 I=1,NQ
IJ1=IJ+I-1
IF(IBIG.EQ.1) THEN
WRITE(INP2,2320)(C(J),J=IJ,IJ1)
ELSE
WRITE(INP2,2450)(C(J),J=IJ,IJ1)
WRITE(IOUT,2450)(C(J),J=IJ,IJ1)
ENDIF
IJ=IJ+NQ
1000 CONTINUE
C....................................................................
IF(LOPT(10).GT.0) GO TO 1040
IF(LOPT(4).LT.1) GO TO 1210
C....................................................................
C CHECK THE FORCE CONSTANTS TO SEE WHICH FORMAT TO USE, PRINT .
C IN FILE IPUN,IOUT,INP2 .
C....................................................................
1010 IF(NUMIT.GT.0) WRITE(IOUT,2460)
REWIND INP2
JTRI=NQ*(NQ+1)/2
IBIG=0
DO 1020 J=1,JTRI
IF(C(J).LE.-10.0D0.OR.C(J).GE.100.0D0) IBIG=1
1020 CONTINUE
IJ=1
IF(LOPT(5).NE.0) WRITE(IPUN,2310)
DO 1030 I=1,NQ
IJ1=IJ+I-1
IF(IBIG.EQ.1) THEN
IF(NUMIT.GE.1.AND.LOPT(24).EQ.0) WRITE(IOUT,2320) (C(J),J=IJ,IJ1)
WRITE(INP2,2320)(C(J),J=IJ,IJ1)
IF (LOPT(5).GT.0) WRITE(IPUN,2320) (C(J),J=IJ,IJ1)
ELSE
IF(NUMIT.GE.1.AND.LOPT(24).EQ.0) WRITE(IOUT,2450) (C(J),J=IJ,IJ1)
WRITE(INP2,2450)(C(J),J=IJ,IJ1)
IF (LOPT(5).GT.0) WRITE(IPUN,2450) (C(J),J=IJ,IJ1)
ENDIF
IJ=IJ+NQ
1030 CONTINUE
IF(LOPT(4).GE.1) GO TO 1210
C....................................................................
C FIRST PART OF THE FLETCHER POWELL PROCEDURE (FLT1) .
C....................................................................
1040 DO 1050 I=1,NQ
1050 CCC(I)=QQ1(I)
IF(LOPT(13).EQ.1) GO TO 1080
IFLT=1
C....................................................................
C CHECK TO SEE IF LAST STEP ALONG FLETCHER-POWELL VECTOR IS MADE.
C....................................................................
1060 IF(ETA(IFLT).EQ.ZERO) GO TO 1450
DO 1070 I=1,NQ
QQ(I)=QQQ(I)
QQ1(I)=ETA(IFLT)*CCC(I)
1070 CC(I)=QQ1(I)
WRITE(IOUT,2470) ETA(IFLT)
GO TO 1210
C....................................................................
C SECOND PART OF THE FLETCHER POWELL PROCEDURE (FLT2) .
C....................................................................
1080 IJ=1
IF(ENERGY(3).GE.0.0D0) GO TO 1120
DO 1090 I=1,3
CI(IJ)=1
CI(IJ+1)=ETA(I)
CI(IJ+2)=ETA(I)**2
1090 IJ=IJ+3
CALL OSINV1(CI,3,D,1.0E-8,L,M)
IJ=0
DO 1110 I=1,3
S=ZERO
DO 1100 J=1,3
IJ=IJ+1
1100 S=S+CI(IJ)*ENERGY(J)
1110 AE(I)=S
ETA(4)=-AE(2)/(TWO*AE(3))
ENERGY(4)=ETA(4)*(ETA(4)*AE(3)+AE(2)) +AE(1)
GO TO 1130
1120 WRITE(IOUT,*) 'FLAMDA=',FLAMDA
FLAMDA=FLAMDA*ANG/GDYN
ELAMDA=(ENERGY(1)-ENERGY(2))/ETA(1)+FLAMDA
ETA(4)=FLAMDA*ETA(1)/(2.0D0*ELAMDA)
ENERGY(4)=ENERGY(2)-FLAMDA*ETA(4)/2.0D0
1130 IFLT=4
DO 1140 I=1,NQ
QQ(I)=QQQ(I)
QQ1(I)=ETA(IFLT)*CCC(I)
1140 CC(I)=QQ1(I)
WRITE(IOUT,2480) ENERGY(4)
WRITE(IOUT,2490) ETA(4)
GO TO 1210
1150 CONTINUE
C....................................................................
C WRITE OUT ORIGINAL INTERNAL COORDINATES, DISPLACEMENTS .
C FOR ONE DISTORTED GEOMETRY AT A TIME (DISP OPTION) .
C THE PROGRAM LOOPS BACK TO 1160 UNTIL II = # DISPLACEMENTS .
C....................................................................
WRITE(IOUT,2500)
WRITE(IOUT,2510) (QQ(J),J=1,NQ)
II=0
1160 II=II+1
DO 1170 J=1,4
INDT(J)=INDI(J,II)
1170 CIN(J)=CCIN(J,II)
WRITE(IOUT,2200)
WRITE(IOUT,2520) (INDT(J),CIN(J),J=1,4)
DO 1180 J=1,NQ
CC(J)=ZERO
1180 CONTINUE
DO 1190 J=1,4
J1=INDT(J)
IF (J1.LE.0) GO TO 1190
CC(J1) = CIN(J)
1190 CONTINUE
DO 1200 J=1,NQ
1200 QQ1(J)=CC(J)
GO TO 1250
C....................................................................
C MAKE B MATRIX, THEN (B*M*B+)-1 IN C .
C....................................................................
1210 DO 1220 I=1,NCARD
BACKSPACE INP
1220 CONTINUE
CALL MACHB(NEK,B,NCMAX,NQMAX,XA,YA,ZA,QQ,NADT,IX,IOUT,NQ,.FALSE.,
1 .FALSE.,NCARD)
I1=0
DO 1240 I=1,NQ
DO 1240 J=1,NQ
I1=I1+1
S=ZERO
DO 1230 K=1,NEK
1230 S=S+B(K,I)*B(K,J)*XM(K)
1240 C(I1)=S
CALL OSINV1(C,NQ,D,TOL,L,M)
1250 CONTINUE
C....................................................................
C NOW TRANSFORM THE INTERNAL DISPLACEMENTS TO CARTESIAN .
C DISPLACEMENTS BY DELTA X = (B*M*B+)-1 * B*M * (DELTA Q) .
C THIS IS THE SAME TRANSFORMATION USED TO CONVERT CARTESIAN .
C FORCES TO INTERNAL FORCES, AND CAN BE USED BECAUSE THE .
C DERIVATIVE WITH RESPECT TO A COORDINATE AND A COORDINATE ARE .