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I'm very curious on this and I would appreciate it if someone could answer my question on this subject, as I don't have the most experience, and I know there's programmers out there who could assist me on my question. thank you if you do decide to help! |
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[Naive Approach] By Counting Nodes – O(n) time and O(1) space: [Expected Approach] By Tortoise and Hare Algorithm – O(n) time and O(1) space: In case of odd number of nodes in the linked list, slow_ptr will reach the middle node when fast_ptr will reach the last node and in case of even number of nodes in the linked list, slow_ptr will reach the middle node when fast_ptr will become NULL. |
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[Naive Approach] By Counting Nodes – O(n) time and O(1) space:
The idea is to traversing the entire linked list once to count the total number of nodes. After determining the total count, traverse the list again and stop at the (count/2)th node to return its value. This method requires two passes through the linked list to find the middle element.
[Expected Approach] By Tortoise and Hare Algorithm – O(n) time and O(1) space:
We can use the Hare and Tortoise Algorithm to find the middle of the linked list. Traverse linked list using a slow pointer (slow_ptr) and a fast pointer (fast_ptr ). Move the slow pointer to the next node(one node forward) and the fast pointer to the next of the next…