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Copy pathZigZagConversion.java
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ZigZagConversion.java
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/*
*The string "PAYPALISHIRING" is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility)
* P A H N
* A P L S I I G
* Y I R
*And then read line by line: "PAHNAPLSIIGYIR"The string "PAYPALISHIRING" is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility)
*Write the code that will take a string and make this conversion given a number of rows:
*string convert(string text, int nRows);
*convert("PAYPALISHIRING", 3) should return "PAHNAPLSIIGYIR".ne by line: "PAHNAPLSIIGYIR"
*Write the code that will take a string and make this conversion given a number of rows:
*string convert(string text, int nRows);
*convert("PAYPALISHIRING", 3) should return "PAHNAPLSIIGYIR".
*Write the code that will take a string and make this conversion given a number of rows:
*string convert(string text, int nRows);
*convert("PAYPALISHIRING", 3) should return "PAHNAPLSIIGYIR".
*/
class Solution {
public String convert(String s, int numRows) {
char[] ch = s.toCharArray();
StringBuffer[] sb = new StringBuffer[numRows];
for (int i = 0; i < sb.length; i++) {
sb[i] = new StringBuffer();
}
for (int i = 0; i < numRows; ) {
for (int idx = 0; idx < numRows && i < s.length(); idx++) {
sb[idx].append(ch[i++]);
}
for (int idx = numRows - 2; idx >= 1 && i < s.length(); idx--) {
sb[idx].append(ch[i++]);
}
}
for (int idx = 1; idx < sb.length; idx++) {
sb[0].append(sb[idx]);
}
return sb[0].toString();
}
}