-
Notifications
You must be signed in to change notification settings - Fork 0
/
Copy pathDay 31 Edit Distance.cpp
70 lines (47 loc) · 1.42 KB
/
Day 31 Edit Distance.cpp
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
PROBLEM:
Given two words word1 and word2, find the minimum number of operations required to convert word1 to word2.
You have the following 3 operations permitted on a word:
Insert a character
Delete a character
Replace a character
Example 1:
Input: word1 = "horse", word2 = "ros"
Output: 3
Explanation:
horse -> rorse (replace 'h' with 'r')
rorse -> rose (remove 'r')
rose -> ros (remove 'e')
Example 2:
Input: word1 = "intention", word2 = "execution"
Output: 5
Explanation:
intention -> inention (remove 't')
inention -> enention (replace 'i' with 'e')
enention -> exention (replace 'n' with 'x')
exention -> exection (replace 'n' with 'c')
exection -> execution (insert 'u')
SOLUTION:
class Solution {
public:
int minDistance(string word1, string word2) {
int i,j,n,m;
n = word1.size();
m = word2.size();
vector<vector<int>> dp(n+1,vector<int>(m+1,0));
for(i=0;i<=n;i++)
{
for(j=0;j<=m;j++)
{
if(i==0)
dp[i][j]=j;
else if(j==0)
dp[i][j]=i;
else if(word1[i-1] == word2[j-1])
dp[i][j] = dp[i-1][j-1];
else
dp[i][j] = 1 + min({dp[i-1][j],dp[i][j-1],dp[i-1][j-1]});
}
}
return dp[n][m];
}
};