Reformatting #13
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Hey there! I didn't understand the reformatting of the cipher we got. I understand the removal of (nil), &, + and = but I don't understand how the order changed. Can you help me out? |
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Replies: 1 comment 3 replies
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The order is different because of little endian. Little end stores the least significant byte first. We're more used to a big endian format where the most significant byte is stored first. |
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Thank you for the instant reply mate. Is it hard to convert text from little endian to big endian? |
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The only difference between little and big endian is the order the bytes appear in. For the Stonks question, for every block of 4 characters, the order is reversed. If it was 12345678 in big endian, it would be 43218765 in little endian. Notice it's just reversing the sequence of bytes every set interval |
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Oh thanks a lot mate. Helped me a lot :D |
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The order is different because of little endian. Little end stores the least significant byte first. We're more used to a big endian format where the most significant byte is stored first.