Implement the following operations of a queue using stacks.
-
push(x) -- Push element x to the back of queue.
-
pop() -- Removes the element from in front of queue.
-
peek() -- Get the front element.
-
empty() -- Return whether the queue is empty. Notes:
-
You must use only standard operations of a stack -- which means only
push to top
,peek/pop from top
,size
, andis empty
operations are valid. -
Depending on your language, stack may not be supported natively. You may simulate a stack by using a list or deque (double-ended queue), as long as you use only standard operations of a stack.
-
You may assume that all operations are valid (for example, no pop or peek operations will be called on an empty queue).
使用两个栈模拟队列
首先定义channel(first, second)操作,表示把第一个栈逐一弹出,并压入第二个栈:
void channel(stack<int> &src, stack<int> &dest) {
while (!src.empty()) {
dest.push(src.top());
src.pop();
}
}
- push(), push时往第一个栈压入
- empty(), 当且仅当两个栈都为空时,队列空
- peek(), 若第二个栈为空,则channel(first, second), 返回second.top()
- pop(), 若第二个栈为空,则channel(first, second), second.pop()
bool empty(void) {
return first.empty() && second.empty();
}
void push(int x) {
first.push(x);
}
int peek(void) {
if (second.empty()) {
channel(first, second);
}
return second.top();
}
void pop(void) {
if (second.empty()) {
channel(first, second);
}
second.pop();
}