Find the contiguous subarray within an array (containing at least one number) which has the largest sum.
For example, given the array [−2,1,−3,4,−1,2,1,−5,4], the contiguous subarray [4,−1,2,1] has the largest sum = 6.
click to show more practice. More practice:
If you have figured out the O(n) solution, try coding another solution using the divide and conquer approach, which is more subtle.
最大连续之和经典题
int maxSubArray(int *a, int n)
{
if (a == NULL || n <= 0)
return 0;
int max = a[0], sum = a[0];
for (int i = 1; i < n; ++i) {
if (sum < 0)
sum = a[i];
else
sum += a[i];
max = MAX(max, sum);
}
return max;
}
Maximum Product Subarray: 最大连续之积