README.md

Nth Highest Salary

Write a SQL query to get the nth highest salary from the Employee table.

+----+--------+
| Id | Salary |
+----+--------+
| 1  | 100    |
| 2  | 200    |
| 3  | 300    |
+----+--------+

For example, given the above Employee table, the nth highest salary where n = 2 is 200. If there is no nth highest salary, then the query should return null.

Solution

同 SecondHighestSalary

mysql 函数

mysql 可以自定义过程（无返回值）和函数（有返回值），参数也可以定义为IN或者OUT,IN就是传人的参数,OUT就是要写进去的参数（有点像传引用）

语法:

CREATE
    [DEFINER = { user | CURRENT_USER }]
    PROCEDURE sp_name ([proc_parameter[,...]])
    [characteristic ...] routine_body

CREATE
    [DEFINER = { user | CURRENT_USER }]
    FUNCTION sp_name ([func_parameter[,...]])
    RETURNS type
    [characteristic ...] routine_body

proc_parameter:
    [ IN | OUT | INOUT ] param_name type

func_parameter:
    param_name type

type:
    Any valid MySQL data type

characteristic:
    COMMENT 'string'
  | LANGUAGE SQL
  | [NOT] DETERMINISTIC
  | { CONTAINS SQL | NO SQL | READS SQL DATA | MODIFIES SQL DATA }
  | SQL SECURITY { DEFINER | INVOKER }

routine_body:
    Valid SQL routine statement

定义例子:

delimiter //
CREATE PROCEDURE simpleproc (OUT param1 INT)
 BEGIN
	SELECT COUNT(*) INTO param1 FROM t;
END//

使用call simpleproc(@count)调用以上过程，然后select @count输出结果

定义函数例子:

delimiter $$
drop function if exists getNthHighestSalary $$
CREATE FUNCTION getNthHighestSalary(N INT) RETURNS INT
BEGIN
	declare x int;
	set N = N - 1;
	set x = (select distinct Salary from Employee order by Salary desc limit N, 1);
	if isnull(x)
		then
		return null;
	else
		return x;
	end if;
END$$
delimiter ;

调用select hello('world');输出Hello, world!

mysql变量

mysql使用declare 变量名 变量类型声明变量, 使用set 变量名 = 值设置变量值

mysql分支循环

if语句
if(condition) then s1;
elseif (condition) then s2;
else s3;
end if;

[begin_label:]while 循环
while condition do
s1;
s2;
end while[end_label]

Code

CREATE FUNCTION getNthHighestSalary(N INT) RETURNS INT
BEGIN
	declare x int;
	set N = N - 1;
	set x = (select distinct Salary from Employee order by Salary desc limit N, 1);
	if isnull(x)
		then
		return null;
	else
		return x;
	end if;
END