-
Notifications
You must be signed in to change notification settings - Fork 0
/
Copy path114.二叉树展开为链表.cpp
71 lines (67 loc) · 1.37 KB
/
114.二叉树展开为链表.cpp
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
/*
* @lc app=leetcode.cn id=114 lang=cpp
*
* [114] 二叉树展开为链表
*
* https://leetcode-cn.com/problems/flatten-binary-tree-to-linked-list/description/
*
* algorithms
* Medium (64.92%)
* Likes: 171
* Dislikes: 0
* Total Accepted: 13.4K
* Total Submissions: 20.6K
* Testcase Example: '[1,2,5,3,4,null,6]'
*
* 给定一个二叉树,原地将它展开为链表。
*
* 例如,给定二叉树
*
* 1
* / \
* 2 5
* / \ \
* 3 4 6
*
* 将其展开为:
*
* 1
* \
* 2
* \
* 3
* \
* 4
* \
* 5
* \
* 6
*
*/
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
void flatten(TreeNode* root) {
while(root){
if(root->left == NULL) root= root->right;
else {
if(root->right){
TreeNode *l = root->left;
while(l->right) l = l->right;
l->right = root->right;
}
root->right = root->left;
root->left = NULL;
root = root->right;
}
}
}
};