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90.子集-ii.cpp
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/*
* @lc app=leetcode.cn id=90 lang=cpp
*
* [90] 子集 II
*
* https://leetcode-cn.com/problems/subsets-ii/description/
*
* algorithms
* Medium (57.22%)
* Likes: 126
* Dislikes: 0
* Total Accepted: 13.1K
* Total Submissions: 22.9K
* Testcase Example: '[1,2,2]'
*
* 给定一个可能包含重复元素的整数数组 nums,返回该数组所有可能的子集(幂集)。
*
* 说明:解集不能包含重复的子集。
*
* 示例:
*
* 输入: [1,2,2]
* 输出:
* [
* [2],
* [1],
* [1,2,2],
* [2,2],
* [1,2],
* []
* ]
*
*/
class Solution {
public:
vector<vector<int>> subsetsWithDup(vector<int>& nums) {
vector<vector<int>> ans = {{}};
if(nums.empty()) return ans;
sort(nums.begin(), nums.end());
int start = 0;
for(int i=0; i<nums.size(); i++){
int len = ans.size();
if(i>0 && nums[i]!=nums[i-1]) start = 0;
for(int j=start; j<len; j++){
vector<int> tmp = ans[j];
tmp.push_back(nums[i]);
ans.push_back(tmp);
}
start = ans.size() - (len - start);
}
return ans;
}
};