Exc. 1.1

[PaulScemama]

Hi! This is more of a question (albeit perhaps a stupid one), but I do not understand how the derivative of y(x_n,w) in exercise 1.1 is simply (x_n)^i. I see that if we take the derivative with respect to the weights {w} of y(x_n,w), it is \sum_{j=1}^{M} (x_n)^j ? How does that turn into (x_n)^i? If you could elaborate on that step, It would be much appreciated!

Thank you!

[fabraz]

Hello @PaulScemama, take a look at this answer. It may help you.