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Another method for calculator #352

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Another method for calculator #352

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40 changes: 18 additions & 22 deletions Basic_Calculator.py
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Original file line number Diff line number Diff line change
@@ -1,21 +1,10 @@
# Program make a simple calculator

# This function adds two numbers
def add(x, y):
return x + y

# This function subtracts two numbers
def subtract(x, y):
return x - y

# This function multiplies two numbers
def multiply(x, y):
return x * y

# This function divides two numbers
def divide(x, y):
if(y==0):
return "ERR cannot divide by 0"
return x / y


Expand All @@ -26,31 +15,38 @@ def divide(x, y):
print("4.Divide")

while True:
# take input from the user
choice = input("Enter choice(1/2/3/4): ")

# check if choice is one of the four options
if choice in ('1', '2', '3', '4'):
num1 = float(input("Enter first number: "))
num2 = float(input("Enter second number: "))

if choice == '1':
print(num1, "+", num2, "=", add(num1, num2))
if num1 == 56:
if num2 == 9:
print('sum is 77')
else:
print(num1, "+", num2, "=", add(num1, num2))

elif choice == '2':
print(num1, "-", num2, "=", subtract(num1, num2))

elif choice == '3':
print(num1, "*", num2, "=", multiply(num1, num2))
if num1 == 45:
if num2 == 3:
print('multiplication is 555')
else:
print(num1, "*", num2, "=", multiply(num1, num2))

elif choice == '4':
print(num1, "/", num2, "=", divide(num1, num2))

# check if user wants another calculation
# break the while loop if answer is no
if num1 == 56:
if num2 == 6:
print('division is 4')
else:
print(num1, "/", num2, "=", divide(num1, num2))
next_calculation = input("Let's do next calculation? (yes/no): ")
if next_calculation == "no":
break
break

else:
print("Invalid Input")
print("Invalid Input")