Use regex to remove all instances of var/ in proc args #677
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What this PR does
So basically when you have a proc you need args in it /proc(args...)
You don't need var/arg
This runs a regex to replace all instances of var/
You can do this yourself by running the following substitution
Search: (^/[\w/][^ \t]+(.*)(var/|, ?var/.*)(.*))
Replace: $1$3