Added solution to Q33 of Leetcode under issue #23

leetCode Solutions/Q33_SearchInRotatedSortedArray/Q33_SearchInRotatedSortedArray.cpp

@@ -0,0 +1,39 @@
+/*
+As the array is sorted but rotated, so we figure out
+which half of array is sorted, once we know which half of the array is
+sorted, we perform a binary search to search for the target.
+
+Complexity Analysis
+TC(Time Complexity): O(log(N))  //Binary Search
+SC(Space Complexity): O(1)   //Constant Extra Space Used
+*/
+class Solution {
+public:
+    int search(vector<int>& nums, int target) {
+        int n=nums.size();
+        int low=0;
+        int high=n-1;
+        while(low<=high){
+            int mid=(low+high)/2;
+            if(nums[mid]==target)
+                return mid;
+            //Checking if Left half is sorted
+            if(nums[low]<=nums[mid])
+            {
+                if(nums[low]<=target&&nums[mid]>target)
+                    high=mid-1;
+                else
+                    low=mid+1;
+            }
+            //Checking if Right half is sorted
+            else
+            {
+                if(nums[high]>=target&&nums[mid]<target)
+                    low=mid+1;
+                else
+                    high=mid-1;
+            }
+        }
+        return -1;  //if target not found
+    }
+};