try to added python solution for no.1

001. Single Number/README.md

@@ -1,3 +1,5 @@
+# 思路(C++)
+
 昨晚看C++ Primer 5th的[习题5.14](https://github.com/pezy/Cpp-Primer/blob/master/ch05/ex5_14.cpp)
 想了很常规的解法，但脑子里一直都在想有没有更好的方案，因为这道题很像是在一篇文章里检索连续的高频词。应该是非常常见的才对。
 但因为多了一个要求**连续**的条件，所以却又不太一样。
@@ -18,3 +20,9 @@ C++ Primer 5th ==> 4.8. The Bitwise Operators ==> Bitwise AND, OR, and XOR Opera
 异或(^)的特点是: **按位，同为0，异为1。**
 
 所以这道题要找"落单"那哥们，就将他们全部异或，相同的小伙伴异或后为0了，可不就剩下那个老光棍了么。
+
+## Python
+
+心血来潮用 python 再刷一遍, 这道题有一种更简洁的写法是用 `reduce`. 为啥我只用了最简单的 `for` 循环呢?
+
+请见 <https://stackoverflow.com/questions/181543/what-is-the-problem-with-reduce>

001. Single Number/main.cpp

@@ -8,6 +8,4 @@ int main()
     Solution s;
     int A[7] = {1,2,3,5,2,1,3};
     std::cout << s.singleNumber(A, 7) << std::endl;
-
-	return 0;
 }

001. Single Number/solution.py

@@ -0,0 +1,15 @@
+class Solution:
+    def singleNumber(self, nums):
+        """
+        :type nums: List[int]
+        :rtype: int
+        """
+        single = 0
+        for num in nums:
+            single ^= num
+        return single
+
+
+# test
+if __name__ == '__main__':
+    print(Solution().singleNumber([2, 4, 5, 4, 5, 2, 6, 7, 7]))

README.md

@@ -5,7 +5,7 @@ LeetCode solutions in C++ 11. (From Easy to Hard)
 
 |NO.|Title|Solution|Add Date|Difficulty|
 |---|-----|--------|--------|----------|
-|1|[Single Number][1]|[C++](001.%20Single%20Number/solution.h)|2014/10/15|Medium|
+|1|[Single Number][1]|[C++](001.%20Single%20Number/solution.h)|[Python](001.%20Single%20Number/solution.py)|2014/10/15|Medium|
 |2|[Maximum Depth of Binary Tree][2]|[C++](002.%20Maximum%20Depth%20of%20Binary%20Tree/solution.h)|2014/10/16|Easy|
 |3|[Same Tree][3]|[C++](003.%20Same%20Tree/solution.h)|2014/10/17|Easy|
 |4|[Reverse Integer][4]|[C++](004.%20Reverse%20Integer/solution.h)|2014/10/18|Easy|