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import operator | ||
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from constraint import Problem,RecursiveBacktrackingSolver | ||
import networkx as nx | ||
import node | ||
from node import extend | ||
import resolve | ||
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def rank(tree): | ||
@extend(node.number) | ||
def _rank(self): | ||
problem.addVariable(id(self),[0]) | ||
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@extend(node.let) | ||
def _rank(self): | ||
if isinstance(self.ret,node.ident): | ||
# plain assignment -- not a field, lhs indexing | ||
vars = [id(self.ret), id(self.args)] | ||
try: | ||
problem.addVariables(vars,range(4)) | ||
problem.addConstraint(operator.__eq__,vars) | ||
except ValueError: | ||
pass | ||
else: | ||
# lhs indexing or field | ||
pass | ||
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@extend(node.for_stmt) | ||
def _rank(self): | ||
vars = [id(self.ident), id(self.expr)] | ||
problem.addVariables(vars,range(4)) | ||
problem.addConstraint((lambda u,v: u+1==v),vars) | ||
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@extend(node.if_stmt) | ||
def _rank(self): | ||
# could use operator.__not__ instead of lambda expression | ||
problem.addVariable(id(self.cond_expr),range(4)) | ||
problem.addConstraint(lambda t: t==0, [id(self.cond_expr)]) | ||
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@extend(node.ident) | ||
def _rank(self): | ||
try: | ||
x = id(self) | ||
problem.addVariable(x,range(4)) | ||
for other in self.defs: | ||
y = id(other) | ||
try: | ||
problem.addVariable(y,range(4)) | ||
except ValueError: | ||
pass | ||
problem.addConstraint(operator.__eq__, [x,y]) | ||
except: | ||
print "Ignored ",self | ||
""" | ||
@extend(funcall) | ||
def rank(self,problem): | ||
if not isinstance(self.func_expr,ident): | ||
# In MATLAB, chaining subscripts, such as size(a)(1) | ||
# is not allowed, so only fields and dot expressions | ||
# go here. In Octave, chaining subscripts is allowed, | ||
# and such expressions go here. | ||
return | ||
try: | ||
if defs.degree(self.func_expr): | ||
# If a variable is defined, it is not a function, | ||
# except function handle usages, such as | ||
# foo=@size; foo(17) | ||
# which is not handled properly yet. | ||
x = id(self.func_expr) | ||
n = len(self.args) | ||
problem.addVariable(x,range(4)) | ||
problem.addConstraint((lambda u: u>=n),[x]) | ||
return | ||
except TypeError: # func_expr is unhashable | ||
# For example [10 20 30](2) | ||
return | ||
except KeyError: | ||
# See tests/clear_margins.m | ||
return | ||
assert getattr(self.func_expr,"name",None) | ||
# So func_expr is an undefined variable, and we understand | ||
# it's a function call -- either builtin or user-defined. | ||
name = self.func_expr.name | ||
# if name not in builtins: | ||
# # User-defined function | ||
# return | ||
# builtins[name](self,problem) | ||
# | ||
#@extend(expr) | ||
#def rank(self,problem): | ||
# try: | ||
# builtins[self.op](self,problem) | ||
# except: | ||
# pass | ||
""" | ||
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problem = Problem(RecursiveBacktrackingSolver()) | ||
for v in node.postorder(tree): | ||
for u in v: | ||
try: | ||
u._rank() | ||
except AttributeError: | ||
pass | ||
s = problem.getSolution() | ||
if not s: | ||
print "No solutions" | ||
else: | ||
d = set() | ||
#for k in sorted(G.nodes(), key=lambda t: (t.name,t.lexpos)): | ||
for k in node.postorder(tree): | ||
if isinstance(k,node.ident): | ||
print k.name,k.lineno, s.get(id(k),-1) | ||
#if not k.name in d and s[id(k)]: | ||
# print "%s(%d)" % (k.name,s[id(k)]) | ||
# d.add(k.name) |