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This final assignment target is to find odd and even number by using repetition and else if technique.

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Nurunnajwa12/Finding-Odd-and-Even-Number

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Finding Odd and Even House Number

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This program should be able to find and display the list of all even,odd and semi-detached house number.

Target

  • Display the even house number
  • Display the odd house number
  • Display the semi-detached house number.

Code Explanation

  • We do repetition until the specified number is find.
    System.out.print("\nOdd house number are : ");
         int odd=0;
         for (z=0;z<array.length;z=z+1)
  • To find odd number , use array[object name]%2 !=0.
  • If the number that calculate by using ampersand with two not equal to zero, the number is odd number
  • Eg: 3%2 = 1 , 1 !=0, therefore 3 is odd number. We have satisfied the condition of code above.
if(array[z]% 2 !=0)
            {
                System.out.print(array[z]+" ");
                odd=1;
            }
  • The same code applied to even number
if(array[z]%2==0)
             {
                 System.out.print(array[z]+" ");
                 even=1;
             }
  • For semi detached house, the house number must belong from 6 until 15
 if (array[z]>=6 && array[z]<=15)
              {
                  System.out.print(array[z]+" ");
                  semi=1;
              }

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This final assignment target is to find odd and even number by using repetition and else if technique.

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