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0.4.2
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semantic-release authored and qorrect committed Apr 16, 2022
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16 changes: 16 additions & 0 deletions CHANGELOG.md
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<!--next-version-placeholder-->

## v0.4.2 (2022-04-16)
### Fix
* Fixes enforce typing breaking on subscripted generics by forking and providing a flag to ignore this non-error. ([`cb19cbc`](https://github.com/prql/PyPrql/commit/cb19cbc81275b291856818fd5689881007d5ee3c))

### Documentation
* **index.md:** Add docs badge to docs ([`3029853`](https://github.com/prql/PyPrql/commit/3029853a76dfc0952e2e2904e6ffede3019c3726))
* **README.md:** Add ReadTheDocs ([`4d5404c`](https://github.com/prql/PyPrql/commit/4d5404c6c5a34375bcb8a8472f9d18265024f471))
* **docs:** Add tests to the sphinx build ([`049ff35`](https://github.com/prql/PyPrql/commit/049ff353e37b180201228c45411713ef73f78761))
* **tests:** Document tests ([`950e55d`](https://github.com/prql/PyPrql/commit/950e55dbaef0579b7e72664d51de0cea50b7ef6b))
* **README.md:** Add badges ([`c176d65`](https://github.com/prql/PyPrql/commit/c176d65e22f091f8ac6db7a03a2a0745a7f37139))
* ***:** Correct urls ([`0622add`](https://github.com/prql/PyPrql/commit/0622add58fdb0dcf271102ac69f4a6dc71eb2ff5))
* **README.md:** Get those badges ([`2547540`](https://github.com/prql/PyPrql/commit/2547540aee2108b6c326e219e1a21bed35ca2a8d))
* **LICENSE:** Add license ([`7119bec`](https://github.com/prql/PyPrql/commit/7119bec4a80a1f4b11c4134bf034d5dcf8dbca41))
* **docs:** Add Sphinx support ([`f966f34`](https://github.com/prql/PyPrql/commit/f966f349d6c81f31f8abd87f929addb4b73d2e81))
* ***:** Provide docstrings throughout ([`c1b7b6d`](https://github.com/prql/PyPrql/commit/c1b7b6dc18db481f8c678cf09811afa3a25d9988))

## v0.4.1 (2022-04-14)
### Fix
* Fixes #27 ([`b666dd0`](https://github.com/qorrect/PyPrql/commit/b666dd03135bb209431575f5d1481e29299576cd))
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2 changes: 1 addition & 1 deletion pyproject.toml
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[tool.poetry]
name = "pyprql"
version = "0.4.1"
version = "0.4.2"
description = "Python Implementation of Pipelined Relational Query Language (PRQL)"
authors = ["qorrect <[email protected]>", "rbpatt2019 <[email protected]>"]
license = "Apache-2.0"
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2 changes: 1 addition & 1 deletion pyprql/__init__.py
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import pyprql.lang.prql as prql # noqa: F401
from pyprql.lang.prql import to_sql as to_sql # noqa: F401

__version__ = "0.4.1"
__version__ = "0.4.2"

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