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130 changes: 130 additions & 0 deletions project_euler/problem_095/sol1.py
Original file line number Diff line number Diff line change
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"""
Project Euler Problem 95: https://projecteuler.net/problem=95

Amicable Chains

Solution is doing the following:
- Get relevant prime numbers
- Iterate over product combination of prime numbers to generate all non-prime
numbers up to max number, by keeping track of prime factors
- Calculate the sum of factors for each number
- Iterate over found some factors to find longest chain

>>> solution(200000)
12496

"""

from numpy import sqrt


def sum_primes(factor_d, num):
"""
Calculates the sum of factors from all prime exponents.

>>> sum_primes({2: 1, 3: 1}, 6)
6
"""
tot = 1
for p in factor_d:
comp = 0
ex_factor = 1
for _ in range(factor_d[p] + 1):
comp += ex_factor
ex_factor *= p
tot *= comp
return tot - num


def generate_primes(n: int):
"""
Calculates the list of primes up to and including n.

>>> generate_primes(6)
[2, 3, 5]
"""
primes = [True] * (n + 1)
primes[0] = primes[1] = False
for i in range(2, int(sqrt(n + 1)) + 1):
if primes[i]:
j = i * i
while j <= n:
primes[j] = False
j += i
primes_list = []
for i in range(2, len(primes)):
if primes[i]:
primes_list += [i]
return primes_list


def multiply(chain, primes, prime, prev_n, n_max, prev_sum, primes_d):
"""
Run over all prime combinations to generate non-prime numbers.

>>> multiply([None] * 3, {2}, 2, 1, 2, 0, {})
"""

number = prev_n * prime
primes_d[prime] = primes_d.get(prime, 0) + 1
if prev_n % prime != 0:
new_sum = prev_sum * (prime + 1) + prev_n
else:
new_sum = sum_primes(primes_d, number)
chain[number] = new_sum
for p in primes:
if p >= prime:
number_n = p * number
if number_n > n_max:
break
multiply(chain, primes, p, number, n_max, new_sum, primes_d.copy())


def find_longest_chain(chain, n_max):
"""
Finds the smallest element and length of longest chain

>>> find_longest_chain([0, 0, 0, 0, 0, 0, 6], 6)
(6, 1)
"""

length_max = 0
elem_max = 0
for i in range(2, len(chain)):
start = i
length = 1
el = chain[i]
visited = {i}
while el > 1 and el <= n_max and el not in visited:
length += 1
visited.add(el)
el = chain[el]

if el == start and length > length_max:
length_max = length
elem_max = start

return elem_max, length_max


def solution(n_max: int = 1000000) -> int:
"""
Runs the calculation for numbers <= n_max.

>>> solution(10)
6
"""

primes = generate_primes(n_max)
chain = [0] * (n_max + 1)
for p in primes:
if p * p > n_max:
break
multiply(chain, primes, p, 1, n_max, 0, {})

chain_start, _ = find_longest_chain(chain, n_max)
return chain_start


if __name__ == "__main__":
print(f"{solution() = }")