Neetcode.io Solutions in Python

This repository contains Python solutions for all problems covered on Neetcode.io, organized for easy reference and learning. Each solution is written with clarity and includes comments explaining the approach, time complexity, and space complexity.

More language support (e.g., Java, JavaScript, Golang) will be added soon, making this repository a one-stop solution for Neetcode.io problems in multiple languages.

🌟 Features

• Comprehensive Coverage: Solutions for all Neetcode.io problem categories.
• Well-Commented Code: Every solution includes a detailed explanation of the approach.
• Optimized Algorithms: Focus on clean, efficient, and scalable solutions.
• Future Expansion: Planned support for solutions in other languages like Java, C++, and JavaScript.

📂 Directory Structure

The repository is organized into folders based on problem categories:

• 📦 Neetcode.io Solutions
  • Arrays & Hashing
  • Two Pointers
  • Sliding Window
  • Stack
  • Binary Search
  • Linked List
  • Trees
  • Heap / Priority Queue
  • Backtracking
  • Tries
  • Graphs
  • Advanced Graphs
  • 1-D Dynamic Programming
  • 2-D Dynamic Programming
  • Greedy
  • Intervals
  • Math & Geometry
  • Bit Manipulation

Each problem is organized into its own folder within the relevant category, making finding and reviewing solutions easy.

🛠 How to Use

1. Clone the repository:

   git clone https://github.com/aniketshukla1/DSA-Neetcode-Solutions.git

2. Navigate to the category and problem folder you’re interested in:

   cd Arrays/Contains Duplicate/

3. Open the Solution.py file to view the solution:

   cat Solution.py

📖 Solution Format

Each solution file follows a consistent format: • Problem Name: Title of the problem. • Problem Description: A short summary of the problem. • Approach: Explanation of the solution approach. • Complexity: Analysis of time and space complexity. • Code: Optimized Python solution.

🧩 Example

File: Solution.py

# Problem: Contains Duplicate
# Description: Check if a list contains any duplicates.
# Approach:
# 1. Use a set to track unique elements (O(1) for lookup/insertion).
# 2. Iterate through the list:
#    - If an element exists in the set, return True (duplicate found).
#    - Otherwise, add the element to the set.
# 3. If no duplicates are found after iteration, return False.
# Time Complexity: O(n), Space Complexity: O(n).

from typing import List

class Solution:
    def containsDuplicate(self, nums: List[int]) -> bool:
        unique_nums = set()
        for num in nums:
            if num in unique_nums:
                return True
            unique_nums.add(num)
        return False

🚀 Contributions

Contributions are welcome! If you’d like to add solutions in other languages or optimize existing ones: 1. Fork the repository. 2. Add your solutions. 3. Submit a pull request.

📚 References • Neetcode.io • LeetCode

📜 License

This repository is licensed under the MIT License. You may use the code for your personal learning and projects.