Added Python solution for "985. Sum of Even Numbers After Queries"

09/85/m985.py

@@ -0,0 +1,31 @@
+# Solved:
+# (M) Sum of Even Numbers After Queries
+# https://leetcode.com/problems/sum-of-even-numbers-after-queries/
+
+from typing import List
+
+
+class Solution:
+    def sumEvenAfterQueries(self, nums: List[int], queries: List[List[int]]) -> List[int]:
+        res = [0] * len(queries)
+        s = sum([n for n in nums if n % 2 == 0])
+
+        for i, row in enumerate(queries):
+            n = nums[row[1]]
+            # If next number to be replaced was even, subtract its value from sum
+            if n & 1 == 0:
+                s -= n
+            n += row[0]
+            # If new value is even, add it to sum
+            if n & 1 == 0:
+                s += n
+
+            nums[row[1]] = n
+            res[i] = s
+
+        return res
+
+
+x = Solution()
+print(x.sumEvenAfterQueries(nums=[1, 2, 3, 4], queries=[[1, 0], [-3, 1], [-4, 0], [2, 3]]))
+print(x.sumEvenAfterQueries(nums=[1], queries=[[4, 0]]))