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New Problem Solution - "1877. Minimize Maximum Pair Sum in Array"
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minimizeMaximumPairSumInArray/MinimizeMaximumPairSumInArray.cpp
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// Source : https://leetcode.com/problems/minimize-maximum-pair-sum-in-array/ | ||
// Author : Hao Chen | ||
// Date : 2021-11-12 | ||
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/***************************************************************************************************** | ||
* | ||
* The pair sum of a pair (a,b) is equal to a + b. The maximum pair sum is the largest pair sum in a | ||
* list of pairs. | ||
* | ||
* For example, if we have pairs (1,5), (2,3), and (4,4), the maximum pair sum would be | ||
* max(1+5, 2+3, 4+4) = max(6, 5, 8) = 8. | ||
* | ||
* Given an array nums of even length n, pair up the elements of nums into n / 2 pairs such that: | ||
* | ||
* Each element of nums is in exactly one pair, and | ||
* The maximum pair sum is minimized. | ||
* | ||
* Return the minimized maximum pair sum after optimally pairing up the elements. | ||
* | ||
* Example 1: | ||
* | ||
* Input: nums = [3,5,2,3] | ||
* Output: 7 | ||
* Explanation: The elements can be paired up into pairs (3,3) and (5,2). | ||
* The maximum pair sum is max(3+3, 5+2) = max(6, 7) = 7. | ||
* | ||
* Example 2: | ||
* | ||
* Input: nums = [3,5,4,2,4,6] | ||
* Output: 8 | ||
* Explanation: The elements can be paired up into pairs (3,5), (4,4), and (6,2). | ||
* The maximum pair sum is max(3+5, 4+4, 6+2) = max(8, 8, 8) = 8. | ||
* | ||
* Constraints: | ||
* | ||
* n == nums.length | ||
* 2 <= n <= 10^5 | ||
* n is even. | ||
* 1 <= nums[i] <= 10^5 | ||
******************************************************************************************************/ | ||
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class Solution { | ||
public: | ||
int minPairSum(vector<int>& nums) { | ||
sort(nums.begin(), nums.end()); | ||
int i = 0, j = nums.size() - 1; | ||
int m = 0; | ||
for(int i = 0, j = nums.size() - 1; i < j; i++,j--) { | ||
m = max(m, nums[i] + nums[j]); | ||
} | ||
return m; | ||
} | ||
}; |