New Problem Solution - "1827. Minimum Operations to Make the Array In…

…creasing"

README.md

@@ -9,6 +9,7 @@ LeetCode
 
 | # | Title | Solution | Difficulty |
 |---| ----- | -------- | ---------- |
+|1827|[Minimum Operations to Make the Array Increasing](https://leetcode.com/problems/minimum-operations-to-make-the-array-increasing/) | [C++](./algorithms/cpp/minimumOperationsToMakeTheArrayIncreasing/MinimumOperationsToMakeTheArrayIncreasing.cpp)|Easy|
 |1825|[Finding MK Average](https://leetcode.com/problems/finding-mk-average/) | [C++](./algorithms/cpp/findingMkAverage/FindingMkAverage.cpp)|Hard|
 |1824|[Minimum Sideway Jumps](https://leetcode.com/problems/minimum-sideway-jumps/) | [C++](./algorithms/cpp/minimumSidewayJumps/MinimumSidewayJumps.cpp)|Medium|
 |1823|[Find the Winner of the Circular Game](https://leetcode.com/problems/find-the-winner-of-the-circular-game/) | [C++](./algorithms/cpp/findTheWinnerOfTheCircularGame/FindTheWinnerOfTheCircularGame.cpp)|Medium|

algorithms/cpp/minimumOperationsToMakeTheArrayIncreasing/MinimumOperationsToMakeTheArrayIncreasing.cpp

@@ -0,0 +1,57 @@
+// Source : https://leetcode.com/problems/minimum-operations-to-make-the-array-increasing/
+// Author : Hao Chen
+// Date   : 2021-04-20
+
+/***************************************************************************************************** 
+ *
+ * You are given an integer array nums (0-indexed). In one operation, you can choose an element of the 
+ * array and increment it by 1.
+ * 
+ * 	For example, if nums = [1,2,3], you can choose to increment nums[1] to make nums = [1,3,3].
+ * 
+ * Return the minimum number of operations needed to make nums strictly increasing.
+ * 
+ * An array nums is strictly increasing if nums[i] < nums[i+1] for all 0 <= i < nums.length - 1. An 
+ * array of length 1 is trivially strictly increasing.
+ * 
+ * Example 1:
+ * 
+ * Input: nums = [1,1,1]
+ * Output: 3
+ * Explanation: You can do the following operations:
+ * 1) Increment nums[2], so nums becomes [1,1,2].
+ * 2) Increment nums[1], so nums becomes [1,2,2].
+ * 3) Increment nums[2], so nums becomes [1,2,3].
+ * 
+ * Example 2:
+ * 
+ * Input: nums = [1,5,2,4,1]
+ * Output: 14
+ * 
+ * Example 3:
+ * 
+ * Input: nums = [8]
+ * Output: 0
+ * 
+ * Constraints:
+ * 
+ * 	1 <= nums.length <= 5000
+ * 	1 <= nums[i] <= 10^4
+ ******************************************************************************************************/
+
+class Solution {
+public:
+    int minOperations(vector<int>& nums) {
+        int ins = 0;
+        int top = nums[0];
+        for(int i = 1; i < nums.size(); i++) {
+            if (nums[i] > top){
+                top = nums[i];
+            }else{
+                ins += (top - nums[i] + 1);
+                top++;
+            }
+        }
+        return ins;
+    }
+};