New Problem Solution - "1822. Sign of the Product of an Array"

README.md

@@ -9,6 +9,7 @@ LeetCode
 
 | # | Title | Solution | Difficulty |
 |---| ----- | -------- | ---------- |
+|1822|[Sign of the Product of an Array](https://leetcode.com/problems/sign-of-the-product-of-an-array/) | [C++](./algorithms/cpp/signOfTheProductOfAnArray/SignOfTheProductOfAnArray.cpp)|Easy|
 |1819|[Number of Different Subsequences GCDs](https://leetcode.com/problems/number-of-different-subsequences-gcds/) | [C++](./algorithms/cpp/numberOfDifferentSubsequencesGcds/NumberOfDifferentSubsequencesGcds.cpp)|Hard|
 |1818|[Minimum Absolute Sum Difference](https://leetcode.com/problems/minimum-absolute-sum-difference/) | [C++](./algorithms/cpp/minimumAbsoluteSumDifference/MinimumAbsoluteSumDifference.cpp)|Medium|
 |1817|[Finding the Users Active Minutes](https://leetcode.com/problems/finding-the-users-active-minutes/) | [C++](./algorithms/cpp/findingTheUsersActiveMinutes/FindingTheUsersActiveMinutes.cpp)|Medium|

algorithms/cpp/signOfTheProductOfAnArray/SignOfTheProductOfAnArray.cpp

@@ -0,0 +1,51 @@
+// Source : https://leetcode.com/problems/sign-of-the-product-of-an-array/
+// Author : Hao Chen
+// Date   : 2021-04-11
+
+/***************************************************************************************************** 
+ *
+ * There is a function signFunc(x) that returns:
+ * 
+ * 	1 if x is positive.
+ * 	-1 if x is negative.
+ * 	0 if x is equal to 0.
+ * 
+ * You are given an integer array nums. Let product be the product of all values in the array nums.
+ * 
+ * Return signFunc(product).
+ * 
+ * Example 1:
+ * 
+ * Input: nums = [-1,-2,-3,-4,3,2,1]
+ * Output: 1
+ * Explanation: The product of all values in the array is 144, and signFunc(144) = 1
+ * 
+ * Example 2:
+ * 
+ * Input: nums = [1,5,0,2,-3]
+ * Output: 0
+ * Explanation: The product of all values in the array is 0, and signFunc(0) = 0
+ * 
+ * Example 3:
+ * 
+ * Input: nums = [-1,1,-1,1,-1]
+ * Output: -1
+ * Explanation: The product of all values in the array is -1, and signFunc(-1) = -1
+ * 
+ * Constraints:
+ * 
+ * 	1 <= nums.length <= 1000
+ * 	-100 <= nums[i] <= 100
+ ******************************************************************************************************/
+
+class Solution {
+public:
+    int arraySign(vector<int>& nums) {
+        int negtive=0;
+        for(auto& n : nums) {
+            if (n==0) return 0;
+            if (n < 0) negtive++;
+        }
+        return negtive % 2 == 0 ? 1 : -1;
+    }
+};