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feat: implement mostTupleOfSuccess methods πŸš€ ✨
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oldratlee committed May 24, 2024
1 parent 4b33e95 commit 8cfcf6d
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Showing 5 changed files with 325 additions and 124 deletions.
82 changes: 79 additions & 3 deletions cffu-core/src/main/java/io/foldright/cffu/CffuFactory.java
Original file line number Diff line number Diff line change
Expand Up @@ -301,7 +301,7 @@ public final <T> Cffu<T>[] toCffuArray(CompletionStage<T>... stages) {
//
// - allOf / allOfFastFail
// - allResultsOf / allResultsOfFastFail
// - allResultsOf / allResultsOfFastFail
// - mostResultsOfSuccess
////////////////////////////////////////////////////////////////////////////////

/**
Expand Down Expand Up @@ -423,15 +423,13 @@ public final <T> Cffu<List<T>> allResultsOfFastFail(CompletionStage<? extends T>
* the given stages in the given time({@code timeout}), aka as many results as possible in the given time.
* <p>
* If the given stage is successful, its result is the completed value; Otherwise the given valueIfNotSuccess.
* (aka the result extraction logic is {@link Cffu#getSuccessNow(Object)}).
*
* @param timeout how long to wait in units of {@code unit}
* @param unit a {@code TimeUnit} determining how to interpret the {@code timeout} parameter
* @param valueIfNotSuccess the value to return if not completed successfully
* @param cfs the stages
* @see Cffu#getSuccessNow(Object)
*/
// TODO * @see CompletableFutureUtils#MGetSuccessNow(Object, CompletionStage[])
@Contract(pure = true)
@SafeVarargs
public final <T> Cffu<List<T>> mostResultsOfSuccess(
Expand Down Expand Up @@ -495,6 +493,7 @@ public final <T> Cffu<T> anyOfSuccess(CompletionStage<? extends T>... cfs) {
//
// - allTupleOf
// - allTupleOfFastFail
// - mostTupleOfSuccess
////////////////////////////////////////////////////////////////////////////////

/**
Expand Down Expand Up @@ -633,6 +632,83 @@ public <T1, T2, T3, T4, T5> Cffu<Tuple5<T1, T2, T3, T4, T5>> allTupleOfFastFail(
return new0(CompletableFutureUtils.allTupleOfFastFail(cf1, cf2, cf3, cf4, cf5));
}

/**
* Returns a new Cffu with the most results in the <strong>same order</strong> of
* the given two stages in the given time({@code timeout}), aka as many results as possible in the given time.
* <p>
* If the given stage is successful, its result is the completed value; Otherwise the value {@code null}.
*
* @param timeout how long to wait in units of {@code unit}
* @param unit a {@code TimeUnit} determining how to interpret the {@code timeout} parameter
* @return a new Cffu that is completed when the given two stages complete
* @see #mostResultsOfSuccess(long, TimeUnit, Object, CompletionStage[])
* @see Cffu#getSuccessNow(Object)
*/
@Contract(pure = true)
public <T1, T2> Cffu<Tuple2<T1, T2>> mostTupleOfSuccess(
long timeout, TimeUnit unit, CompletionStage<? extends T1> cf1, CompletionStage<? extends T2> cf2) {
return new0(CompletableFutureUtils.mostTupleOfSuccess(timeout, unit, cf1, cf2));
}

/**
* Returns a new Cffu with the most results in the <strong>same order</strong> of
* the given three stages in the given time({@code timeout}), aka as many results as possible in the given time.
* <p>
* If the given stage is successful, its result is the completed value; Otherwise the value {@code null}.
*
* @param timeout how long to wait in units of {@code unit}
* @param unit a {@code TimeUnit} determining how to interpret the {@code timeout} parameter
* @return a new Cffu that is completed when the given three stages complete
* @see #mostResultsOfSuccess(long, TimeUnit, Object, CompletionStage[])
* @see Cffu#getSuccessNow(Object)
*/
@Contract(pure = true)
public <T1, T2, T3> Cffu<Tuple3<T1, T2, T3>> mostTupleOfSuccess(
long timeout, TimeUnit unit,
CompletionStage<? extends T1> cf1, CompletionStage<? extends T2> cf2, CompletionStage<? extends T3> cf3) {
return new0(CompletableFutureUtils.mostTupleOfSuccess(timeout, unit, cf1, cf2, cf3));
}

/**
* Returns a new Cffu with the most results in the <strong>same order</strong> of
* the given four stages in the given time({@code timeout}), aka as many results as possible in the given time.
* <p>
* If the given stage is successful, its result is the completed value; Otherwise the value {@code null}.
*
* @param timeout how long to wait in units of {@code unit}
* @param unit a {@code TimeUnit} determining how to interpret the {@code timeout} parameter
* @return a new Cffu that is completed when the given four stages complete
* @see #mostResultsOfSuccess(long, TimeUnit, Object, CompletionStage[])
* @see Cffu#getSuccessNow(Object)
*/
@Contract(pure = true)
public <T1, T2, T3, T4> Cffu<Tuple4<T1, T2, T3, T4>> mostTupleOfSuccess(
long timeout, TimeUnit unit,
CompletionStage<? extends T1> cf1, CompletionStage<? extends T2> cf2,
CompletionStage<? extends T3> cf3, CompletionStage<? extends T4> cf4) {
return new0(CompletableFutureUtils.mostTupleOfSuccess(timeout, unit, cf1, cf2, cf3, cf4));
}

/**
* Returns a new Cffu with the most results in the <strong>same order</strong> of
* the given five stages in the given time({@code timeout}), aka as many results as possible in the given time.
* <p>
* If the given stage is successful, its result is the completed value; Otherwise the value {@code null}.
*
* @param timeout how long to wait in units of {@code unit}
* @param unit a {@code TimeUnit} determining how to interpret the {@code timeout} parameter
* @return a new Cffu that is completed when the given five stages complete
* @see #mostResultsOfSuccess(long, TimeUnit, Object, CompletionStage[])
* @see Cffu#getSuccessNow(Object)
*/
@Contract(pure = true)
public <T1, T2, T3, T4, T5> Cffu<Tuple5<T1, T2, T3, T4, T5>> mostTupleOfSuccess(
long timeout, TimeUnit unit,
CompletionStage<? extends T1> cf1, CompletionStage<? extends T2> cf2, CompletionStage<? extends T3> cf3,
CompletionStage<? extends T4> cf4, CompletionStage<? extends T5> cf5) {
return new0(CompletableFutureUtils.mostTupleOfSuccess(timeout, unit, cf1, cf2, cf3, cf4, cf5));
}

////////////////////////////////////////////////////////////////////////////////
//# Delay Execution, equivalent to same name static methods of CompletableFuture
//
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