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Fixed drawing on vectors and forms
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krystophny committed Mar 30, 2019
1 parent 3e28a10 commit a240211
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22 changes: 10 additions & 12 deletions fig/manifold2.tpx
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Expand Up @@ -16,10 +16,9 @@
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Expand Down Expand Up @@ -67,11 +66,10 @@
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Expand All @@ -85,14 +83,14 @@
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34 changes: 5 additions & 29 deletions writeup_diffgeom.lyx
Original file line number Diff line number Diff line change
Expand Up @@ -1700,33 +1700,9 @@ Local basis
\end_inset

for 2-forms.
While vectors can be interpreted as arrows
\emph on
along
\emph default
a curve, covectors appear as fluxes
\emph on
across
\emph default
a level hypersurface
\begin_inset Formula $\ph=\mathrm{const}$
\end_inset

in direction of the gradient of
\begin_inset Formula $\ph(X)$
\end_inset

.
In
\begin_inset Formula $2D$
\end_inset

, hypersurface coincide with curves, and the 2-form provides the area as
a
\begin_inset Formula $2D$
\end_inset

volume element.
While a vector can be interpreted as an arrow originating at a point, covectors
appear as rates of change on lines connecting two points.
A 2-form describes a flux through a 2D cell bounded by line elements.

\begin_inset CommandInset label
LatexCommand label
Expand Down Expand Up @@ -3503,15 +3479,15 @@ This is also consistent the form
\begin{align}
\v{\omega}_{B} & =\v d\v A=\v d(A_{k}\v dx^{k})=\v dA_{k}\wedge\v dx^{k}=\frac{\partial A_{k}}{\partial x^{i}}\v dx^{i}\wedge\v dx^{k}\nonumber \\
& =\left(\frac{\partial A_{2}}{\partial x^{1}}-\frac{\partial A_{1}}{\partial x^{2}}\right)\v dx^{1}\wedge\v dx^{2}+\left(\frac{\partial A_{3}}{\partial x^{2}}-\frac{\partial A_{2}}{\partial x^{3}}\right)\v dx^{2}\wedge\v dx^{3}+\left(\frac{\partial A_{1}}{\partial x^{3}}-\frac{\partial A_{3}}{\partial x^{1}}\right)\v dx^{3}\wedge\v dx^{1}\nonumber \\
& =\varepsilon^{ijk}\frac{\partial}{\partial x^{j}}A_{k}\,\v dx^{j}\wedge\v dx^{k}.
& =\frac{\partial}{\partial x^{j}}A_{k}\,\v dx^{j}\wedge\v dx^{k}.
\end{align}

\end_inset

We thus can again identify
\begin_inset Formula
\begin{equation}
B_{jk}=\varepsilon^{ijk}\frac{\partial}{\partial x^{j}}A_{k}=\mathcal{B}^{i}
\varepsilon^{ijk}B_{jk}=\varepsilon^{ijk}\frac{\partial}{\partial x^{j}}A_{k}=\mathcal{B}^{i}
\end{equation}

\end_inset
Expand Down

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