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Corrections + 4000 question benchmark
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landy8697 committed Apr 13, 2024
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188 changes: 165 additions & 23 deletions corrections.js
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Expand Up @@ -324,10 +324,10 @@ corrections = {
"credit": "bibob or emptiespace"
},
"Columbia Invitational 17-18, #16": {
"question": "Using just the letters in the alphabet, how many unique 26-letter sequences are possible?",
"answer": "37",
"explanation": "Gm...\n\nit is 26 to power 26... equal 6156119580207157310796674288400203776..\n\nmethinks answer thus 37..\n\nRB",
"credit": "Craig buszka"
"question": "",
"answer": "26",
"explanation": "Idk what the answer is exactly, so I'm reverting to original answer. However, previous correction's logic is incomplete. There are 26^26 ways of choosing the letters, but some are equivalent. if your sequence contains 3 copies of the same letter, then this method would count that sequence 3^2=9 times. These copies must be removed, thus making a drastically smaller answer",
"credit": "BirdyBirdyBirdyBird"
},
"RobertYL, daily fermi questions day #131 [2019 New Trier Q10]": {
"question": "How many licks to the center of a tootsie pop?",
Expand Down Expand Up @@ -528,9 +528,9 @@ corrections = {
"credit": ""
},
"Captains Tryouts Carmel 17-18, #5": {
"question": "How many pennies are in $5645",
"answer": "",
"explanation": "",
"question": "",
"answer": "6",
"explanation": "how hard is it to add 2",
"credit": ""
},
"SSSS Fermi (luminosityfan) 17-18, #20": {
Expand Down Expand Up @@ -762,10 +762,10 @@ corrections = {
"credit": "JazzyX"
},
"RobertYL, daily fermi questions day #35 [2019 Solon Q9]": {
"question": "",
"answer": "10",
"explanation": "bruv look it up",
"credit": "Ryan park"
"question": "What is the distance from Pluto to the sun in kilometers?",
"answer": "9",
"explanation": "average distance is 5.9billion km according to NASA",
"credit": "john"
},
"Columbia Invitational 17-18, #47": {
"question": "",
Expand Down Expand Up @@ -805,9 +805,9 @@ corrections = {
},
"RobertYL, daily fermi questions day #105 [2019 Polytechnic Q24]": {
"question": "",
"answer": "-9",
"explanation": "probability of being struck in lifetime = 6.5e-5; if we assume that the probability of getting struck per day is x, then (1 - x) ^ (80 * 365 days) = 1 - 6.5e-5; solving gives x is around 2.2 * 10^-9",
"credit": "Ryan PARK"
"answer": "-6",
"explanation": "bro is lying through his teeth",
"credit": "bibob"
},
"RobertYL, daily fermi questions day #60 [2019 Boca Raton Tryouts Q11]": {
"question": "",
Expand All @@ -828,9 +828,9 @@ corrections = {
"credit": "emptiespace"
},
"University of Florida North Regional 17-18, #47": {
"question": "How many hours would it take the world\u2019s fastest plane to fly the Earth's orbit?",
"answer": "",
"explanation": "",
"question": "",
"answer": "0",
"explanation": "Fastest plan goes 11850 km/h. Circumference of Earth is ~40,075 km. 40,075/11850 is ~3.38",
"credit": ""
},
"SSSs Fermi (luminosityfan) 17-18, #21": {
Expand Down Expand Up @@ -907,8 +907,8 @@ corrections = {
},
"UChicago Invitational 22-23, #14": {
"question": "",
"answer": "-4",
"explanation": "the \"height\" of a piece of paper refers to the dimensions of the paper along its surface, not its thickness",
"answer": "-10",
"explanation": "that answers in meters assuming its 1 sheet",
"credit": ""
},
"University of Florida North Regional 17-18, #38": {
Expand Down Expand Up @@ -1501,9 +1501,9 @@ corrections = {
},
"Centerville Invitational 17-18, #8": {
"question": "",
"answer": "-8",
"explanation": "mi to km is 1:1600, km to cm is 1:100000, so its -3-5=-8",
"credit": ""
"answer": "-5",
"explanation": "the ratio is 1:1.7 for miles to kilometers, not 1:1600.",
"credit": "Mang223"
},
"UT Austin Regionals 22-23, #5": {
"question": "What is the probability that everyone in a family of 4 survives the virus? [Virus that escaped containment, kills 90% of population]",
Expand Down Expand Up @@ -1636,6 +1636,120 @@ corrections = {
"answer": "4",
"explanation": "Real earth radius = 6 million meters, real Jupiter radius = 70 million meters. Soccer ball has a radius of 11 cm, so scaled down Jupiter would have a radius of 70/6 * 0.11 = 1.28m, and a volume of 4/3*pi*(1.28)^3 = 8.8m^3 = 8800 L \u2014> 4",
"credit": ""
},
"High Desert Mini Invitational 22-23, #4": {
"question": "",
"answer": "13",
"explanation": "30 trillion --> 13 according to https://www.healthline.com/health/number-of-cells-in-body",
"credit": ""
},
"FermiSweat, Fermi Questions, but butter (chicken), #17": {
"question": "",
"answer": "5",
"explanation": "According to this source (might be wrong), https://rentechdigital.com/smartscraper/business-report-details/india/restaurants, there are 250k restaurants in India, meaning we would have to visit 125k --> 5, in order to have a 50% chance of finding the correct one. Other sources site 500k - 1M restaurants but I have not seen anything above 1M so the answer should still be 5",
"credit": ""
},
"RobertYL, daily fermi questions day #93 [2018 Iolani Q17]": {
"question": "",
"answer": "-9",
"explanation": "google",
"credit": ""
},
"RobertYL, daily fermi questions day #6 [2019 WWPS Q4]": {
"question": "",
"answer": "53",
"explanation": "(3.8e26 W) * (3.2e7 s) / (1e-19 J) = ~1.2e53",
"credit": "errorfunction"
},
"High Desert Satellite Invitational 23-24, #18": {
"question": "",
"answer": "19",
"explanation": "4.17*10^12 m^3 -> 4.17*10^18 cm^3, an m&m takes up about 0.65 cm of space so 4.17/0.65 * 10^18 which is clearly 19.",
"credit": "bibob"
},
"Yale Invitational 17-18, #24": {
"question": "Muons have a half life of 1.56*10^-6 seconds. I stand at rest and observe a million muon particles travel from one end of a 10^4 meter tunnel to another end, at velocity v=0.8c, where c is the speed of light. How many muons reach the end?",
"answer": "",
"explanation": "",
"credit": ""
},
"High Desert Satellite Invitational 23-24, #20": {
"question": "",
"answer": "7",
"explanation": "Baseball volume is ~2e-1 L, Olympic swimming pool is 2.5e6 L, so number is 2.5e6 / 2e-1 which is about 1e7, so the answer is 7.",
"credit": "errorfunction"
},
"UT Austin Invitational 23-24, #21": {
"question": "",
"answer": "1998",
"explanation": "Since the power of n is 999, we only really need the last term to approximate the series, so the sum is 100^999 = 10^1998, meaning the answer is 1998. Note that the ratio of the 99th term to the 100th term is (99/100)^999 = 4.36e-5, so only the 100th term is actually important.",
"credit": "errorfunction"
},
"BirdSO In-Person Invitational 22-23, #8": {
"question": "",
"answer": "10",
"explanation": "Metric ton is 1e6 g, each bill has a mass of about 1 g (according to the US government), so 1e6 * $100 * 100 c/$ = 1e10 cents, so the answer is 10",
"credit": "errorfunction"
},
"MIT Invitational 18-19, #21": {
"question": "",
"answer": "0",
"explanation": "A male cries 1.3 times on average per month. 1/10 of a gram in a liter of coke. 30 days in a month. This is just 0.",
"credit": ""
},
"Carnegie Mellon Invitational 22-23, #32": {
"question": "",
"answer": "2",
"explanation": "Mass of neptune is 10^26, while the mass of earth is 6x10^24. this ratio is 2.",
"credit": "emptiespace"
},
"RobertYL, daily fermi questions day #83 [2019 Centerville Q13]": {
"question": "",
"answer": "22",
"explanation": "10^21 liters in the earths ocean, 1/20 liters per balloon. 22",
"credit": ""
},
"MIT Invitational 21-22, #45": {
"question": "",
"answer": "12",
"explanation": "The US uses 4000 TWh/year=1.4*10^19J/year. Wood has an energy density of 7*10^6J/lb. 1.4*10^19J/year * 1lb/(7*10^6J)=2*10^12lb/year -> 12",
"credit": "BirdyBirdyBirdyBird"
},
"BirdSO In-Person Invitational 22-23, #48": {
"question": "Based on the previous question, if you randomly placed a guess between -98 and 98 for every question, what is the probability that you receive either partial or full credit on every question?",
"answer": "",
"explanation": "Please provide an explanation of the \"previous question\"",
"credit": ""
},
"Duke Invitational 22-23, #23": {
"question": "",
"answer": "5",
"explanation": "its been some time so now its at 195m views with approx 1.5 years ago, thats like 195/450 which is less than 0.5 so now its rounding down. L taylor",
"credit": ""
},
"SSSs Fermi (luminosityfan) 17-18, #15": {
"question": "",
"answer": "10",
"explanation": "Sun diameter (1.4 million km) / 6 inches (phone length) = ~9e9 --> 10",
"credit": "eddyzow"
},
"SSSS Fermi (Adi1008) 17-18, #34": {
"question": "",
"answer": "9",
"explanation": "1 cumulonimbus cloud is 1 million tonnes = 1 billion kg = 1billion liters -> 9",
"credit": "BirdyBirdyBirdyBird"
},
"UChicago Invitational 22-23, #43": {
"question": "",
"answer": "7",
"explanation": "A typical cloud weighs 1 million pounds - some google sources talk about ones weighing much larger, these are the rarest of massive clouds that we can see.",
"credit": ""
},
"Northview Invitational 23-24, #38": {
"question": "",
"answer": "42",
"explanation": "If mogwai reproduce at 5 per 10 seconds, then there are 60 periods of reproduction in a 10-minute period, and so the answer is 5^60",
"credit": ""
}
}
corrections_list = [
Expand Down Expand Up @@ -1971,5 +2085,33 @@ corrections_list = [
"Brown Invitational 22-23, #7",
"University of Michigan Invitational 18-19, #20",
"Brown Invitational 22-23, #7",
"SOUP Invitational 23-24, #40"
"SOUP Invitational 23-24, #40",
"High Desert Mini Invitational 22-23, #4",
"FermiSweat, Fermi Questions, but butter (chicken), #17",
"RobertYL, daily fermi questions day #93 [2018 Iolani Q17]",
"RobertYL, daily fermi questions day #6 [2019 WWPS Q4]",
"High Desert Satellite Invitational 23-24, #18",
"Yale Invitational 17-18, #24",
"RobertYL, daily fermi questions day #105 [2019 Polytechnic Q24]",
"Yale Invitational 17-18, #24",
"University of Florida North Regional 17-18, #47",
"High Desert Satellite Invitational 23-24, #20",
"UT Austin Invitational 23-24, #21",
"BirdSO In-Person Invitational 22-23, #8",
"RobertYL, daily fermi questions day #35 [2019 Solon Q9]",
"Centerville Invitational 17-18, #8",
"Yale Invitational 17-18, #24",
"MIT Invitational 18-19, #21",
"Carnegie Mellon Invitational 22-23, #32",
"RobertYL, daily fermi questions day #83 [2019 Centerville Q13]",
"MIT Invitational 21-22, #45",
"BirdSO In-Person Invitational 22-23, #48",
"Duke Invitational 22-23, #23",
"UChicago Invitational 22-23, #14",
"SSSs Fermi (luminosityfan) 17-18, #15",
"Captains Tryouts Carmel 17-18, #5",
"Columbia Invitational 17-18, #16",
"SSSS Fermi (Adi1008) 17-18, #34",
"UChicago Invitational 22-23, #43",
"Northview Invitational 23-24, #38"
]
30 changes: 29 additions & 1 deletion corrections/responses.csv
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Original file line number Diff line number Diff line change
Expand Up @@ -415,4 +415,32 @@ volume of earth = 10^20
3/24/2024 22:53:58,"Brown Invitational 22-23, #7 ",,3,Previous correction stated that they have 541 wins. That's a fermi answer of 3. ,BirdyBirdyBirdyBird
3/24/2024 23:28:21,"University of Michigan Invitational 18-19, #20 ",,-9,SEMs have resolutions of 0.5-4 nanometers. That corresponds with -9,
3/25/2024 11:27:09,"Brown Invitational 22-23, #7 ",,3,"the person who corrected it initially claimed that they have 541 wins. assuming this is correct, the answer rounds up to 3 not 2. the original answer is correct.",yert
3/25/2024 18:29:48,"SOUP Invitational 23-24, #40 ",,4,"Real earth radius = 6 million meters, real Jupiter radius = 70 million meters. Soccer ball has a radius of 11 cm, so scaled down Jupiter would have a radius of 70/6 * 0.11 = 1.28m, and a volume of 4/3*pi*(1.28)^3 = 8.8m^3 = 8800 L —> 4",
3/25/2024 18:29:48,"SOUP Invitational 23-24, #40 ",,4,"Real earth radius = 6 million meters, real Jupiter radius = 70 million meters. Soccer ball has a radius of 11 cm, so scaled down Jupiter would have a radius of 70/6 * 0.11 = 1.28m, and a volume of 4/3*pi*(1.28)^3 = 8.8m^3 = 8800 L —> 4",
3/27/2024 14:08:14,"High Desert Mini Invitational 22-23, #4 ",,13,30 trillion --> 13 according to https://www.healthline.com/health/number-of-cells-in-body,
3/27/2024 14:16:14,"FermiSweat, Fermi Questions, but butter (chicken), #17 ",,5,"According to this source (might be wrong), https://rentechdigital.com/smartscraper/business-report-details/india/restaurants, there are 250k restaurants in India, meaning we would have to visit 125k --> 5, in order to have a 50% chance of finding the correct one. Other sources site 500k - 1M restaurants but I have not seen anything above 1M so the answer should still be 5",
3/28/2024 10:38:58,"RobertYL, daily fermi questions day #93 [2018 Iolani Q17] ",,-9,google,
3/28/2024 15:28:50,"RobertYL, daily fermi questions day #6 [2019 WWPS Q4] ",,53,(3.8e26 W) * (3.2e7 s) / (1e-19 J) = ~1.2e53,errorfunction
3/29/2024 9:11:23,"High Desert Satellite Invitational 23-24, #18 ",,19,"4.17*10^12 m^3 -> 4.17*10^18 cm^3, an m&m takes up about 0.65 cm of space so 4.17/0.65 * 10^18 which is clearly 19.",bibob
3/29/2024 9:18:42,"Yale Invitational 17-18, #24 ","Muons have a half life of 5.6*10^-6 seconds. I stand at rest and observe a million muon particles travel from one end of a 104 meter tunnel to another end, at velocity v = 8c, where c is the speed of light. How many muons reach the end?",6,"first of all, the half life of a muon is 2.2*10^-6, not 5.6*10^-6 (but we'll use the latter when making our calculations). A particle traveling at 8c = 2.4*10^9 m/s takes 104/(2.4*10^9) = 4*10^-8 seconds to cross. Clearly this is less than the half-life of the group of muons and so the answer is 6 (since less than half have decayed, or more than 5*10^5 are remaining).",bibob
3/29/2024 12:08:06,"RobertYL, daily fermi questions day #105 [2019 Polytechnic Q24] ",,-6,bro is lying through his teeth,bibob
3/29/2024 12:12:37,"Yale Invitational 17-18, #24 ",,6,"at v = 8c takes 4*10^-8 seconds, clearly less than the half life so answer is 6",bibob
3/29/2024 15:48:41,"University of Florida North Regional 17-18, #47 ",,0,"Fastest plan goes 11850 km/h. Circumference of Earth is ~40,075 km. 40,075/11850 is ~3.38",
3/30/2024 11:05:14,"High Desert Satellite Invitational 23-24, #20 ",,7,"Baseball volume is ~2e-1 L, Olympic swimming pool is 2.5e6 L, so number is 2.5e6 / 2e-1 which is about 1e7, so the answer is 7. ",errorfunction
3/30/2024 11:17:15,"UT Austin Invitational 23-24, #21 ",,1998,"Since the power of n is 999, we only really need the last term to approximate the series, so the sum is 100^999 = 10^1998, meaning the answer is 1998. Note that the ratio of the 99th term to the 100th term is (99/100)^999 = 4.36e-5, so only the 100th term is actually important.",errorfunction
3/30/2024 11:54:15,"BirdSO In-Person Invitational 22-23, #8 ",,10,"Metric ton is 1e6 g, each bill has a mass of about 1 g (according to the US government), so 1e6 * $100 * 100 c/$ = 1e10 cents, so the answer is 10",errorfunction
4/1/2024 8:56:10,"RobertYL, daily fermi questions day #35 [2019 Solon Q9] ",What is the distance from Pluto to the sun in kilometers?,9,average distance is 5.9billion km according to NASA,john
4/1/2024 12:46:08,"Centerville Invitational 17-18, #8 ",,-5,"the ratio is 1:1.7 for miles to kilometers, not 1:1600.",Mang223
4/2/2024 13:21:23,"Yale Invitational 17-18, #24 ","Muons have a half life of 1.56*10^-6 seconds. I stand at rest and observe a million muon particles travel from one end of a 10^4 meter tunnel to another end, at velocity v=0.8c, where c is the speed of light. How many muons reach the end? ",,,
4/4/2024 13:27:44,"MIT Invitational 18-19, #21 ",,0,A male cries 1.3 times on average per month. 1/10 of a gram in a liter of coke. 30 days in a month. This is just 0.,
4/6/2024 8:31:59,"Carnegie Mellon Invitational 22-23, #32 ",,2,"Mass of neptune is 10^26, while the mass of earth is 6x10^24. this ratio is 2.",emptiespace
4/6/2024 8:53:51,"RobertYL, daily fermi questions day #83 [2019 Centerville Q13] ",,22,"10^21 liters in the earths ocean, 1/20 liters per balloon. 22",
4/10/2024 13:14:26,"MIT Invitational 21-22, #45 ",,12,The US uses 4000 TWh/year=1.4*10^19J/year. Wood has an energy density of 7*10^6J/lb. 1.4*10^19J/year * 1lb/(7*10^6J)=2*10^12lb/year -> 12,BirdyBirdyBirdyBird
4/11/2024 11:59:04,"BirdSO In-Person Invitational 22-23, #48 ","Based on the previous question, if you randomly placed a guess between -98 and 98 for every question, what is the probability that you receive either partial or full credit on every question?",,"Please provide an explanation of the ""previous question""",
4/11/2024 17:39:13,"Duke Invitational 22-23, #23 ",,5,"its been some time so now its at 195m views with approx 1.5 years ago, thats like 195/450 which is less than 0.5 so now its rounding down. L taylor",
4/11/2024 17:41:35,"UChicago Invitational 22-23, #14 ",,-10,that answers in meters assuming its 1 sheet,
4/11/2024 19:43:09,"SSSs Fermi (luminosityfan) 17-18, #15 ",,10,Sun diameter (1.4 million km) / 6 inches (phone length) = ~9e9 --> 10,eddyzow
4/12/2024 10:14:19,"Captains Tryouts Carmel 17-18, #5 ",,6,how hard is it to add 2,
4/12/2024 10:33:33,"Columbia Invitational 17-18, #16 ",,26,"Idk what the answer is exactly, so I'm reverting to original answer. However, previous correction's logic is incomplete. There are 26^26 ways of choosing the letters, but some are equivalent. if your sequence contains 3 copies of the same letter, then this method would count that sequence 3^2=9 times. These copies must be removed, thus making a drastically smaller answer",BirdyBirdyBirdyBird
4/12/2024 10:48:39,"SSSS Fermi (Adi1008) 17-18, #34 ",,9,1 cumulonimbus cloud is 1 million tonnes = 1 billion kg = 1billion liters -> 9,BirdyBirdyBirdyBird
4/12/2024 12:27:58,"UChicago Invitational 22-23, #43 ",,7,"A typical cloud weighs 1 million pounds - some google sources talk about ones weighing much larger, these are the rarest of massive clouds that we can see. ",
4/12/2024 12:33:43,"Northview Invitational 23-24, #38",,42,"If mogwai reproduce at 5 per 10 seconds, then there are 60 periods of reproduction in a 10-minute period, and so the answer is 5^60",
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