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Impl ParamCurve
, ParamCurveArclen
for Arc
#378
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@@ -3,11 +3,11 @@ | |
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//! An ellipse arc. | ||
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use crate::{Affine, Ellipse, PathEl, Point, Rect, Shape, Vec2}; | ||
use crate::{Affine, Ellipse, ParamCurve, ParamCurveArclen, PathEl, Point, Rect, Shape, Vec2}; | ||
use core::{ | ||
f64::consts::{FRAC_PI_2, PI}, | ||
iter, | ||
ops::Mul, | ||
ops::{Mul, Range}, | ||
}; | ||
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#[cfg(not(feature = "std"))] | ||
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@@ -171,6 +171,42 @@ fn rotate_pt(pt: Vec2, angle: f64) -> Vec2 { | |
) | ||
} | ||
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impl ParamCurve for Arc { | ||
fn eval(&self, t: f64) -> Point { | ||
let angle = self.start_angle + (self.sweep_angle * t); | ||
sample_ellipse(self.radii, self.x_rotation, angle).to_point() | ||
} | ||
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fn subsegment(&self, range: Range<f64>) -> Self { | ||
Self { | ||
center: self.center, | ||
radii: self.radii, | ||
start_angle: self.start_angle + (self.sweep_angle * range.start), | ||
sweep_angle: self.sweep_angle - (self.sweep_angle * (1.0 - range.end)), | ||
x_rotation: self.x_rotation, | ||
} | ||
} | ||
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fn start(&self) -> Point { | ||
sample_ellipse(self.radii, self.x_rotation, self.start_angle).to_point() | ||
} | ||
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fn end(&self) -> Point { | ||
sample_ellipse( | ||
self.radii, | ||
self.x_rotation, | ||
self.start_angle + self.sweep_angle, | ||
) | ||
.to_point() | ||
} | ||
} | ||
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impl ParamCurveArclen for Arc { | ||
fn arclen(&self, accuracy: f64) -> f64 { | ||
self.path_segments(0.1).perimeter(accuracy) | ||
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. The 0.1 is arbitrary here - I think It is true that arc length of an ellipse is tricky, I believe it involves the incomplete elliptic integral of the second kind. It might also make sense to do Gauss-Legendre integration of the norm of first derivative, which is pretty simple and is likely more "bang for the buck" than going to Bézier. I'm also wondering whether it might make sense to special case the circular case, as I think it's pretty common and also the math is much easier (especially for inverse arc length). But I'm not going to insist on that, as prefer prioritizing making the general case good rather than having a bunch of special cases. There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. I was using the same math being used for the There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. I'm proposing a numerical approximation in #381 (on top of @waywardmonkeys's PR). It needs some more work as the error bounds are not yet as I would've expected, but you can take a look already. |
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} | ||
} | ||
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impl Shape for Arc { | ||
type PathElementsIter<'iter> = iter::Chain<iter::Once<PathEl>, ArcAppendIter>; | ||
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This feels wrong, though I haven't done tests to validate it. My intuition says it should be
self.sweep_angle * (range.end - range.start)
. In any case, the code that's there reduces algebraically toself.sweep_angle * range.end
. It is of course possible I'm missing something.There was a problem hiding this comment.
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I think what I have is wrong. I'll get back into this and see.