Added 10-11-2024 Solution and 11-11-2024 Question

Added 10-11-2024 Solution and 11-11-2024 Question

10-11-2024/Explanation.md

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+#### Program Explanation:
+
+**Why do arrays never get lost?**  
+👉 **Answer**: Because they always have an _index_ to find their way! 😆🔢
+
+This program finds the _next greater element_ for each element in `nums1` from `nums2`. Here’s a detailed explanation:
+
+1. **Input Handling**:
+
+   - The program takes input for `nums1` and `nums2` as space-separated integers.
+   - These inputs are converted into lists of integers for processing.
+
+2. **Logic to Find Next Greater Element**:
+
+   - For each element in `nums1`, the program looks for the next greater element in `nums2` starting from the position right after the current element's index.
+   - If a greater element is found, it is added to the result list (`res`).
+   - If no greater element is found, `-1` is added to `res`.
+
+3. **Nested Loop Explanation**:
+
+   - The outer loop iterates over each element in `nums1`.
+   - The inner loop starts from the next index of the current element in `nums2` and searches for the next greater element.
+
+4. **Output**:
+   - The result list is printed, showing the next greater element for each item in `nums1` or `-1` if none exists.
+
+---
+
+### Example Execution:
+
+**Input:**
+
+```plaintext
+Enter elements for nums1 separated by space: 4 1 2
+Enter elements for nums2 separated by space: 1 3 4 2
+```
+
+**Output:**
+
+```plaintext
+Next greater elements for nums1 in nums2: [-1, 3, -1]
+```

10-11-2024/Solution.py

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+# Declaring Two Arrays
+nums1, nums2 = [], []  # Initialize empty lists for nums1 and nums2
+
+# Input for nums1
+nums1_input = input("Enter elements for nums1 separated by space: ")
+# Convert the input string into a list of integers
+nums1 = [int(x) for x in nums1_input.split()]
+
+# Input for nums2
+nums2_input = input("Enter elements for nums2 separated by space: ")
+# Convert the input string into a list of integers
+nums2 = [int(x) for x in nums2_input.split()]
+
+# Result list to store the next greater elements
+res = []
+
+# Loop through each element in nums1
+for i in range(len(nums1)):
+    found = False  # Flag to track if a greater element is found
+    for j in range(
+        nums2.index(nums1[i]) + 1, len(nums2)
+    ):  # Start searching in nums2 after the current element's position
+        if nums2[j] > nums1[i]:  # Check if a greater element is found
+            res.append(nums2[j])  # Append the next greater element
+            found = True  # Set the flag to true
+            break  # Break out of the loop once found
+    if not found:  # If no greater element is found
+        res.append(-1)  # Append -1 to the result
+
+# Print the result list
+print("Next greater elements for nums1 in nums2:", res)

11-11-2024/Question.md

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+## Question: **Equal Contiguous Array**
+
+**Difficulty Level:** 🟢 Beginner  
+**Domain:** Arrays and Searching
+
+### **Objective:**
+
+Create a program to find the maximum length of a contiguous subarray with an equal number of `0`s and `1`s in a given binary array.
+
+### **Problem Description:**
+
+Given a binary array consisting of only `0`s and `1`s, your task is to identify the longest contiguous subarray that contains an equal number of `0`s and `1`s and return its length.
+
+### **Input:**
+
+- A binary array `arr` where (1 ≤ length ≤ 10,000).
+
+### **Output:**
+
+- An integer representing the length of the longest contiguous subarray with an equal number of `0`s and `1`s.
+
+### **Example:**
+
+#### Input:
+
+```plaintext
+arr = [0, 1, 0]
+```
+
+#### Output:
+
+```plaintext
+2
+```
+
+#### Explanation:
+
+- The subarray `[0, 1]` has an equal number of `0`s and `1`s, and its length is `2`.