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Hide password in log #906

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57 changes: 56 additions & 1 deletion martin/src/pg/pool.rs
Original file line number Diff line number Diff line change
Expand Up @@ -28,7 +28,7 @@ pub struct PgPool {
impl PgPool {
pub async fn new(config: &PgConfig) -> Result<Self> {
let conn_str = config.connection_string.as_ref().unwrap().as_str();
info!("Connecting to {conn_str}");
info!("Connecting to {}", hide_pwd(conn_str));
let (pg_cfg, ssl_mode) = parse_conn_str(conn_str)?;

let id = pg_cfg.get_dbname().map_or_else(
Expand Down Expand Up @@ -96,3 +96,58 @@ async fn get_conn(pool: &Pool, id: &str) -> Result<Object> {
.await
.map_err(|e| PostgresPoolConnError(e, id.to_string()))
}

fn hide_pwd(conn_string: &str) -> String {
let mut new_str = conn_string.to_owned();

if let Some(at_idx) = conn_string.find('@') {
if let Some(colon_idx) = &conn_string[..at_idx].find("://") {
if let Some(pwd_idx) = &conn_string[colon_idx + 3..at_idx].find(':') {
let start = pwd_idx + colon_idx + 4;
let end = at_idx;
new_str.replace_range(start..end, &"*".repeat(end - start));
}
}
} else if let Some(pwd_idx) = conn_string.find("password=") {
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Seems there's still a bug here

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no no, this is not a good way to do this. Regex is built specifically for this type of jobs, or a dedicated postgres connection string parser (which is part of the postgress connection lib, so hard to reuse in a better way). I did submit a better solution to this (IMO) - #907

In general for this type of issues, take a look at documentation -- I would use something like this, you can try it at https://rustexp.lpil.uk/

^postgres(?:ql)?://[^:@/?]+:([^:@/?]+)@ -- the password is captured as the first capture group

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I'm not good at Regex actually I don't like Regex. So glad to see that there is a dedicated parser in other crate lib. Closed.

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The reason I don't like Regex is it's easy to write hard to read later..

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it's not that bad, and it does save you in many cases, so highly advise to embrace it ... sparingly! ;)

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TBH, I don't think the code of this PR is easier to read / understand -- string parsing in code is notoriously non-trivial to understand either

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Agree. I like your #907 🤜

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TBH, I don't think the code of this PR is easier to read / understand -- string parsing in code is notoriously non-trivial to understand either

TBH I'm exhausted to write this PR🤣

let start = pwd_idx + "password=".len();
let mut end = start;
while end < conn_string.len() - 1 && !conn_string[end..].starts_with('&') {
end += 1;
}
new_str.replace_range(start..end, &"*".repeat(end - start));
}
new_str
}
#[cfg(test)]
mod tests {
use super::*;

#[test]
fn test_hide_pwd() {
let conn_strs = [
"abcdefghij...xyz",
";@",
"password=",
"postgresql://localhost/mydb?k1=v1&k2=v2",
"postgresql://localhost/mydb?password=",
"postgresql://localhost/mydb?password=pwd123",
"postgresql://localhost/mydb?password=pwd123&key2=value2",
"postgresql://user@localhost:5432/mydb",
"postgresql://user:password@localhost:5432/mydb",
];
let expecteds = [
"abcdefghij...xyz",
";@",
"password=",
"postgresql://localhost/mydb?k1=v1&k2=v2",
"postgresql://localhost/mydb?password=",
"postgresql://localhost/mydb?password=******",
"postgresql://localhost/mydb?password=pwd123&key2=value2",
"postgresql://user@localhost:5432/mydb",
"postgresql://user:password@localhost:5432/mydb",
];
for (conn_str, expected) in conn_strs.iter().zip(expecteds.iter()) {
assert_eq!(hide_pwd(conn_str), *expected);
}
}
}