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Tutorial: Computing log-determinants of pytree-valued functions (#152)
* Drafted a ravelling example * Formatted the logdeterminant-pytree notebook * Updated docs
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# Log-determinants of pytree-valued functions | ||
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Can we compute log-determinants if the matrix-vector products are pytree-valued? | ||
Yes, we can. Here is how. | ||
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Imports: | ||
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```python | ||
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>>> import jax | ||
>>> import jax.flatten_util # this is important! | ||
>>> import jax.numpy as jnp | ||
>>> | ||
>>> from matfree import slq, montecarlo | ||
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``` | ||
Create a test-problem: a function that maps a pytree (dict) to a pytree (tuple). | ||
Its (regularised) Gauss--Newton Hessian shall be the matrix-vector product | ||
whose log-determinant we estimate. | ||
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```python | ||
>>> def testfunc(x): | ||
... """Map a dictionary to a tuple with some arbitrary values.""" | ||
... return jnp.linalg.norm(x["weights"]), x["bias"] | ||
... | ||
>>> # Create a test-input | ||
>>> b = jnp.arange(1.0, 40.0) | ||
>>> W = jnp.stack([b + 1.0, b + 2.0]) | ||
>>> x0 = {"weights": W, "bias": b} | ||
>>> | ||
>>> # Linearise the functions | ||
>>> f0, jvp = jax.linearize(testfunc, x0) | ||
>>> _f0, vjp = jax.vjp(testfunc, x0) | ||
>>> | ||
>>> # Look at the Jacobians -- oh no, they are pytree-valued | ||
>>> print(jax.tree_util.tree_map(jnp.shape, f0)) | ||
((), (39,)) | ||
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>>> print(jax.tree_util.tree_map(jnp.shape, jvp(x0))) | ||
((), (39,)) | ||
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>>> print(jax.tree_util.tree_map(jnp.shape, vjp(f0))) | ||
({'bias': (39,), 'weights': (2, 39)},) | ||
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``` | ||
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To compute log-determinants, we need to transform the functions and states. | ||
The reason is that the linear algebra that underlies stochastic Lanczos quadrature | ||
has no means of handling arbitrary pytrees -- only matrices and matrix-vector products. | ||
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The transformation we are looking for is "ravelling" a pytree | ||
(think: flattening of the tree). | ||
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```python | ||
>>> x0_flat, unravel_func_x = jax.flatten_util.ravel_pytree(x0) | ||
>>> f0_flat, unravel_func_f = jax.flatten_util.ravel_pytree(f0) | ||
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>>> def matvec(f_flat, alpha=1e-1): | ||
... """Matrix-vector product x -> (J J^\top + \alpha I) x.""" | ||
... f_unravelled = unravel_func_f(f_flat) | ||
... vjp_eval = vjp(f_unravelled) | ||
... matvec_eval = jvp(*vjp_eval) | ||
... f_eval, _unravel_func = jax.flatten_util.ravel_pytree(matvec_eval) | ||
... return f_eval + alpha * f_flat | ||
... | ||
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``` | ||
Now, we can compute the log-determinant with the flattened inputs as usual: | ||
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```python | ||
>>> # Compute the log-determinant | ||
>>> key = jax.random.PRNGKey(seed=1) | ||
>>> sample_fun = montecarlo.normal(shape=f0_flat.shape) | ||
>>> order = 3 | ||
>>> logdet = slq.logdet_spd(order, matvec, key=key, sample_fun=sample_fun) | ||
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>>> # Look at the results | ||
>>> print(jnp.round(logdet, 2)) | ||
3.81 | ||
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>>> # Materialise the matrix-vector product and compute the true log-determinant. | ||
>>> M = jax.jacfwd(matvec)(f0_flat) | ||
>>> print(jnp.round(jnp.linalg.slogdet(M)[1], 2)) | ||
3.81 | ||
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``` |
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