Render template parts with extended cache control.
Install django-viewlet in your python environment
$ pip install django-viewlet
Supports Django
version 1.2 - 1.5 and Python
version 2.6 - 2.7.
Add viewlet
to your INSTALLED_APPS
setting so Django can find the template tag
INSTALLED_APPS = (
...
'viewlet',
)
If you're using Jinja2
as your template engine, put this in your Django settings.
VIEWLET_TEMPLATE_ENGINE = 'jinja2'
If you're using Coffin
or Jingo
, add the ViewletExtension
to their settings,
and optionally switch to their respective environment.
Coffin:
JINJA2_EXTENSIONS = (
...
'viewlet.loaders.jinja2_loader.ViewletExtension',
)
VIEWLET_JINJA2_ENVIRONMENT = 'coffin.common.env'
Jingo:
JINJA_CONFIG = {
'extensions': (
...
'viewlet.loaders.jinja2_loader.ViewletExtension',
),
}
VIEWLET_JINJA2_ENVIRONMENT = 'jingo.get_env'
A viewlet is almost like a function based django view, taking a template context
as first argument instead of request.
Place your viewlets in viewlets.py
or existing views.py
in your django app directory.
from django.template.loader import render_to_string
from viewlet import viewlet
@viewlet
def hello_user(context, name):
return render_to_string('hello_user.html', {'name': name})
You can then render the viewlet with the viewlet
template tag:
{% load viewlets %}
<p>{% viewlet hello_user request.user.username %}</p>
... and in your Jinja2 templates:
<p>{% viewlet 'host_sponsors', host.id) %}</p>
A cached viewlet can be re-rendered and updated behind the scenes with viewlet.refresh
import viewlet
viewlet.refresh('hello_user', 'monkey')
@viewlet(name, template, key, timeout)
- name
- Optional reference name for the viewlet, defaults to function name.
- template
- Optional path to template. If specified the viewlet must return a context dict, otherwise it is responsible to return the rendered output itself.
- key
- Optional cache key, if not specified a dynamic key will be generated
viewlet:name(args...)
- timeout
- Cache timeout. Defaults to configured cache backend default timeout, None = eternal, 0 = uncached.
The content returned by the viewlet will by default be cached. Use the timeout
argument to change this.
@viewlet(timeout=30*60)
def hello_user(context, name):
return render_to_string('hello_user.html', {'name': name})
Tip: Settimeout
toNone
to cache forever and useviewlet.refresh
to update the cache.
Django viewlet will by default build a cache key viewlet:name(args...)
.
To customize this key pass a string to the viewlet decorator argument key
that includes string mod operators for each
viewlet argument.
@viewlet(timeout=30*60, key='some_cache_key_%s')
def hello_user(context, name):
return render_to_string('hello_user.html', {'name': name})
Django viewlet will cache returned context instead of html by using the template
decorator argument.
This is useful if cached html is too heavy, or your viewlet template needs to be rendered on every call.
The specified template will then be rendered with the viewlet context merged with the parent context, usually a RequestContext
.
@viewlet(template='hello_user.html', timeout=30*60)
def hello_user(context, name):
return {'name': name}
Note: Return context dict for the template, not rendered html/text
If there is no need for caching, set the viewlet decorator argument timeout
to 0.
@viewlet(timeout=0)
def hello_user(context, name):
return render_to_string('hello_user.html', {'name': name})
By default your viewlets will be named as the function. To override this you can set the decorator argument name
@viewlet(name='greeting')
def hello_user(context, name):
return render_to_string('hello_user.html', {'name': name})
A powerful usage of viewlet.refresh
is to use it together with Django signals:
class Product(Model):
name = CharField(max_length=255)
@viewlet(timeout=None)
def product_teaser(context, id):
product = get_context_object(Product, id, context)
return render_to_string('product_teaser.html', locals())
def refresh_product_teaser(instance, **kwargs):
viewlet.refresh('product_teaser', instance.id)
post_save.connect(refresh_product_teaser, Product)
Viewlets can also be accesses with AJAX by adding viewlet.urls
to your Django root urls:
urlpatterns = patterns('',
(r'^viewlet/', include('viewlet.urls')),
)
The url ends with the viewlet name followed by a querystring used as kwargs
to the viewlet:
http://localhost:8000/viewlet/[name]/?arg=1...