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Filter: LowPassFilter2p: constrain cuttoff to 40% of sample rate #25175

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Oct 9, 2023
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13 changes: 4 additions & 9 deletions libraries/Filter/LowPassFilter2p.cpp
Original file line number Diff line number Diff line change
Expand Up @@ -17,13 +17,12 @@ DigitalBiquadFilter<T>::DigitalBiquadFilter() {

template <class T>
T DigitalBiquadFilter<T>::apply(const T &sample, const struct biquad_params &params) {
if(is_zero(params.cutoff_freq) || is_zero(params.sample_freq)) {
if(!is_positive(params.cutoff_freq) || !is_positive(params.sample_freq)) {
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@IamPete1 IamPete1 Oct 3, 2023

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This changes to !is_positive to keep the same check as we do here:

if (!is_positive(ret.cutoff_freq)) {
// zero cutoff means pass-thru
return;
}

For example if a user was to set the cutoff to -1 for disable the compute_params function would not update so you would be left with the configutation for the old cutoff and the filter would still work fine because -1 is not zero.

return sample;
}

if (!initialised) {
reset(sample, params);
initialised = true;
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Don't need to set initialised because the reset call does it for us.

void DigitalBiquadFilter<T>::reset(const T &value, const struct biquad_params &params) {
_delay_element_1 = _delay_element_2 = value * (1.0 / (1 + params.a1 + params.a2));
initialised = true;
}

}

T delay_element_0 = sample - _delay_element_1 * params.a1 - _delay_element_2 * params.a2;
Expand All @@ -37,7 +36,6 @@ T DigitalBiquadFilter<T>::apply(const T &sample, const struct biquad_params &par

template <class T>
void DigitalBiquadFilter<T>::reset() {
_delay_element_1 = _delay_element_2 = T();
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No need to zero these setting initialised false will force a reset in the next apply call

initialised = false;
}

Expand All @@ -49,14 +47,15 @@ void DigitalBiquadFilter<T>::reset(const T &value, const struct biquad_params &p

template <class T>
void DigitalBiquadFilter<T>::compute_params(float sample_freq, float cutoff_freq, biquad_params &ret) {
ret.cutoff_freq = cutoff_freq;
// Keep well under Nyquist limit
ret.cutoff_freq = MIN(cutoff_freq, sample_freq * 0.4);
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Using exactly 0,5 still resulted in numerical issues. 0.45 would probably work.

ret.sample_freq = sample_freq;
if (!is_positive(ret.cutoff_freq)) {
// zero cutoff means pass-thru
return;
}

float fr = sample_freq/cutoff_freq;
float fr = ret.sample_freq / ret.cutoff_freq;
float ohm = tanf(M_PI/fr);
float c = 1.0f+2.0f*cosf(M_PI/4.0f)*ohm + ohm*ohm;

Expand Down Expand Up @@ -103,10 +102,6 @@ float LowPassFilter2p<T>::get_sample_freq(void) const {

template <class T>
T LowPassFilter2p<T>::apply(const T &sample) {
if (!is_positive(_params.cutoff_freq)) {
// zero cutoff means pass-thru
return sample;
}
Comment on lines -106 to -109
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Don't need this check as we now check in the main apply function.

return _filter.apply(sample, _params);
}

Expand Down