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homework_02
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Due: Friday, June 15th 9:00AM
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Read: axiomatics and assorted examples in chapter 2
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Problems:
- 3
- 8
- 15c
- 16abc
- 25
- 36
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Theoretical Problems:
- 13
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Let:
- [A^c] be the outcome of events not contained in the space [A]
Two dice are thrown. Let [E] be the event that the sum of the dice is odd, let [F] be the event that at least one of the dice lands on [1], and let [G] be the event that the sum is [5]. Describe the events [EF, E \cup F, FG, EF^c, EFG].
- [EF]
- The expression defines the space where the sum of the dice is [odd] and one die lands on a [1].
- The expression implies that secend device must be [even] as only [1 + even = odd].
- [E \cup F]
- The expression defines the space where
- The sum of the dice is odd.
- One of the dice lands on [1].
- Both the proceeding bullets are true
- The expression defines the space where
- [FG]
- The expression defins the space where one of the dice lands on a [1] and the sum of the dice is [5],
- The expression implies the second dice lands on a [4].
- [EF^c]
- The expression defines the space where the sum of the dice is [odd] and at least one of dice does not land on a [1].
- [EFG]
- The expression defines the space where the sum of the dice is [odd] and at least one of dice land on a [1] and sum of the dice is [5]
- The expression implies that one dice land on a [1] and the other on a [4], a space of two possible outcomes.
Suppose that [A] and [B] are mutually exclusive events for which [P(A) = .3] and [P(B) = .5]. What is the probability that
- either [A] or [B] occurs?
- [P( A \cup B) = P(A) + P(B) = .8 ]
- Keep in mind they are mutually exclusive.
- [P( A \cup B) = P(A) + P(B) = .8 ]
- A occurs but B does not?
- [P( A // B) = P(A) + P(B) - P(B) = P(A) = .30]
- Both A and B occur?
- [P( A \cap B = P(A) + P(B) - P(A \cup B) = 0 ]
If it is assumed that all [52] poker hands are [52 \choose 5] equally likely, what is the probability of being dealt two pairs? (This occurs when the cards have denominations [a, a, b, c, d,] where [a, b, c, d] are all distinct.)
- [ \frac{ {13 \choose 1}{4 \choose 2}{12 \choose 1}{4 \choose 1}} { {2 \choose 1}} {11 \choose 1}{4 \choose 1} ]
Poker dice is played by simultaneously rolling 5 dice. Show that
- (a) [P{no_two_alike} = .0926]
- [ \frac{ {6 \choose 1}{5 \choose 1}{4 \choose 1}{3 \choose 1}{2 \choose 1}}{ {6 \choose 5}} ]
- (b) [P{one_pair} = .4630]
- (c) [P{two_pair} = .2315]
A pair of dice is rolled until a sum of either [5] or [7] appears. Find the probability that a [5] occurs first.
Hint: Let [E_n] denote the event that a [5] occurs on the first [n -1] roll and no [5] or [7] occurs on the first [n − 1] rolls. Compute [P(E_n )] and argue that [ \sum\limits_{n = 1}^{\infty}{ P(E_n )}] is the desired probability.
- Combinations that make a 5
- 1, 4
- 2, 3
- 3, 2
- 4, 1
- Combinations that maek a 7
- 1,6
- 2,5
- 3,4
- 4,3
- 2,5
- 6,1
- Total possible combinations on for a pair of die
- [ {6 \choose 1}{6 \choose 1}]
Two cards are chosen at random from a deck of [52] playing cards. What is the probability that they
- (a) are both aces?
- [\frac{ {4 \choose 2}}{ {52 \choose 2}}]
- (b) have the same value?
- [\frac{ {4 \choose 2}}{ {52 \choose 2}}]
Prove that [P(EF^c) = P(E) − P(EF)]
[E = EF \cup EF^c], since [EF] and [EF^c] are mutually exclusive therefore [P(E) = P(EF) + P(EF^c)] [\Rightarrow P(EF^c) = P(E) -P(EF)]