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homework_09_electric_current
Kurt Robert Rudolph edited this page Jul 4, 2012
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A circuit is constructed with five resistors and a battery as shown. The battery voltage is [V = 12.0 V]. The values for the resistors are: [R_1 = 75.0 \Omega], [R_2 = 118.0 \Omega], [R_3 = 147.0 \Omega] and [R_4 = 61.0 \Omega].
The value for [R_X] is unknown, but it is known that [I_4], the current that flows through resistor [R_4], is zero.
- [V = 12.0 V]
- [R_1 = 75.0 \Omega]
- [R_2 = 118.0 \Omega]
- [R_3 = 147.0 \Omega]
- [R_4 = 61.0 \Omega].
- [I_4 = 0]
What is [I_1], the magnitude of the current that flows through the resistor [R_1]?
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[I = I_1 + I_2]
- [I_b = I_1 + I_2]
- [V_b = V_1 = V_2]
- [I_b = \frac{ V_b}{ R_1} + \frac{ V_b}{ R_2}]
- []
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[\frac{ v}{ R_1}]
- It looks like you have calculated the current assuming that the voltage across [R_1] is the battery voltage, which it is not. The current does not return directly to the battery after leaving [R_1]. Where does it go before returning to the battery?