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prelecture_12_magnetism
- start wit observations about
- bar magnets
- compass needles
- current caring wires
- Well see that magnetic effects can be described by another vector field, appropriately name the magnetic field, that is created by electric charges in motion.
- First will we asses the forces magnetic fields have on
charged particles.
- Larentz Force [\vec F = q \vec E + q \vec v \times \vec B]
- The general equation which describes the force on a charged particle as it moves through regions containing electric and magnetic fields.
- Larentz Force [\vec F = q \vec E + q \vec v \times \vec B]
- We finish by examining a few examples.
- Bar Magnet
- the ends are usually called the Nort and South poles
- opposite poles attract
- like poles repel
- filed around a bar magnet is similar to an electric dipole
- note the triangles in the field represent compass needles small bar magnets able to piviot about their central axis and align with the field in their proximity
- if a bar magnet is cut in half you end up with two bar magnets,
not isolated north and south poles.
We have just discussed what most of you have known since elementary school - that the north pole of one magnet is attracted to the south pole of another magnet. We also know that the needle of a compass is itself a magnet. In view of this, how can we explain that the north pole of a compass needle seems to be attracted to the north pole of the planet Earth?
- The geographic North pole of the earth is actually the South magnetic pole of the Earth.
- Electric Currents create magnetic fields
- all electric fields are created by charges in motion.
- Passing a current through a wire produces magnetic field
and you see according forces between them
-
- same direction produces attractive force
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- opposite direction produces repulsive force
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- Just saw two wires create an electric force on one another
- We find that the magnetic field around a wire is always perpendicular
to the wire and in a clockwise or counter clockwise direction.
- This indicates to us that
- Force is perpendicular to current
- [\vec F \perp \vec I] and [\vec F \perp \vec B]
- Both to the direction of the current and the direction of the magnetic field.
- [\vec F \perp \vec I] and [\vec F \perp \vec B]
- Cross product is a good mathematical model for this
- [\vec F = q \vec v \times \vec B]
- Force is perpendicular to current
- [|\vec A \times \vec B| = A B \sin \theta]
- Right Hand Rules
- Version 1
- Fingers point in direction of [\vec A]
- Curl fingers toward [\vec B]
- Thumb gives direction of [\vec A \times \vec B]
- Version 2
- Point thumb in direction of [\vec A]
- Point fingers in direction of [\vec B]
- Palm gives direction of [\vec A \times \vec B]
- Version 1
The picture below shows a cathode ray tube in a magnetic field. A beam of electrons is produced at the cathode and travels with a high velocity toward a fluorescent screen. In the absence of a magnetic field the beam of electrons would hit the screen at the center (labeled 2 in the picture). When the orientation of the magnetic field is in the [-y] direction as shown, at which of the points on the screen would the beam arrive?
- [1]
- Taking the cross product between the velocity of the electrons ([+z] direction) and the magnetic field ([-y] direction) results in a vector pointing in the [+x] direction. Since the charge of the electrons are negative, however, we have to factor in another minus sign, which makes the resulting force point in the [-x] direction. The beam will therefore strike at the point labeled [1].
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- A device oriented with a long narrow channel ensuring that all particles exiting the tube are traveling in the same direction.
- As well, the device employs a electric and magnetic fields throughout
the channel in order to ensure the particles are traveling at the same speed.
- Orient the fields such that [\vec F_{Electric} = -\vec F_{Magnetic}]
- [q \vec E = - q \vec v \times \vec B] * only particle with that unique speed will now exit the channel * particles with all other speeds will be deflectd by the non-zero combination of the electric and magnetic forces
- [v = \frac{ E}{ B}] when [\vec F_B = -\vec F_B]
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- Force on th particle is the magnetic force [\vec F_B = q \vec v \times \vec B]
- suppose the force of the magnetic field is perpendicular to the velocity
- [F_B = q v B]
- This gives rise to a centripetal acceleration of constant magnitude [a_c = \frac{ v^2}{ R}]
- which gives us [\frac{ q v B}{ m} = \frac{ v^2}{ R}]
- hence [R = \frac{ m v}{ q B}] the radius of the circle
Particle [A] has twice the charge and [4] times the mass of particle [B]. Suppose [A] and [B] have the same kinetic energy [K] and move perpendicular to a constant magnetic field. Which partilce moves in the smallest circle? (It may help you to recall that [K] can be expressed as \frac{ p^2}{ 2m}.)
- Particles [A] and [B] move in circles of the same radius
- [R^2 = \frac{ 2 m k}{ (q B)^2}]
- Doubling the charge [q] and quadrupling the mass [m] leaves [R] unchanged since both the numerator and denominator increase by [4].
- Introduces observations involving forces exerted by bar magnets, and current carrying wires to indicate the existence of magnetic fields.
- All magnetic effects are able to be described in terms of magnetic field that is created by the motion of charged particles
- These magnetic fields create forces on electric charges that are in motion.
We introduced the magnetic form for this in terms of the cross product of vectors.
- [\vec F = q \vec v \times \vec B]