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lecture_02
Kurt Robert Rudolph edited this page Jun 12, 2012
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What is the direction of the electric field at point [A]?
- Right
What is the direction of the electric field at point [B]?
- Left
In which of the two cases shown below is the magnitude of the electric field at the point labeled [A]
- The will be equal.
What is the direction of the electric field at point [P], the unoccupied corner of the square?
- (A) - Up and to the right.
- The [-q] charge is [r = sqrt{ 2d^2}] from [P] and acts on the point with a force of magnitude [\sqrt{ E_x_{-q}^2 + E_y_{-q}^2} = k \frac{ q}{ r} \cos{ \frac{ \pi}{ 4} + \frac{ q}{ r} \sine{ \frac{ \pi}{ 4}]